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Chemical Equations Balanced on 06/08/19

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Balance equation of any chemical reaction online for free
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Na2SO4(s) + HCl(l) = NaCl(s) + SO2(g) + H2O(l) + O2(g) =>
2 Na2SO4(s) + 4 HCl(l) = 4 NaCl(s) + 2 SO2(g) + 2 H2O(l) + O2(g)

Fe + HBr = FeBr3 + H2 =>
2 Fe + 6 HBr = 2 FeBr3 + 3 H2

NaN3 = Na + N2 =>
2 NaN3 = 2 Na + 3 N2

BaCl2 + Na2SO4 = NaCl + BaSO4 =>
BaCl2 + Na2SO4 = 2 NaCl + BaSO4

NaOH + H2S = Na2S + H2O =>
2 NaOH + H2S = Na2S + 2 H2O

Al + Ba(NO3)2 = AlO3 + N2 + BaO =>
5 Al + 3 Ba(NO3)2 = 5 AlO3 + 3 N2 + 3 BaO

CO(NH2)2 + KOH = KCNO + NH3 + H2O =>
CO(NH2)2 + KOH = KCNO + NH3 + H2O

N2 + Cl2 + O2 + H2O = NH4ClO4 =>
N2 + Cl2 + 2 O2 + 4 H2O = 2 NH4ClO4

AgCl + NH4Cl = Ag(NH3)2 + HCl + Cl =>
AgCl + 2 NH4Cl = Ag(NH3)2 + 2 HCl + Cl

Pb(NO3)2 = PbO + NO2 + O2 =>
2 Pb(NO3)2 = 2 PbO + 4 NO2 + O2

NAHCO3 = NAOH + CO2 =>
NAHCO3 = NAOH + CO2

Na + H2So4 = Na2So4 + H2 =>
2 Na + H2So4 = Na2So4 + H2

NH3 + O2 = NO + H2O =>
4 NH3 + 5 O2 = 4 NO + 6 H2O

C3H8 + O2 = CO2 + H2O =>
C3H8 + 5 O2 = 3 CO2 + 4 H2O

H3PO3 = H3PO4 + PH3 =>
4 H3PO3 = 3 H3PO4 + PH3

Na + H2SO4 = Na2SO4 + H2 =>
2 Na + H2SO4 = Na2SO4 + H2

Na + H2SO4 = Na2SO4 + H2 =>
2 Na + H2SO4 = Na2SO4 + H2

Cr2O72{-} + I{-} + H{+} = Cr3{+} + I2 + H2O =>
6 Cr2O72{-} + 854 I{-} + 864 H{+} = 4 Cr3{+} + 427 I2 + 432 H2O

C4H10(g) + O2(g) = CO2(g) + H2O(g) =>
2 C4H10(g) + 13 O2(g) = 8 CO2(g) + 10 H2O(g)

NH3 + CuO = Cu + N2 + H2O =>
2 NH3 + 3 CuO = 3 Cu + N2 + 3 H2O

KMnO4 + HCl = KCl + MnCl2 + H2O + Cl2 =>
2 KMnO4 + 16 HCl = 2 KCl + 2 MnCl2 + 8 H2O + 5 Cl2

Cr2O72{-} + I{-} + H{+} = Cr3{+} + I2 + H2O =>
6 Cr2O72{-} + 854 I{-} + 864 H{+} = 4 Cr3{+} + 427 I2 + 432 H2O

C2H5OH + MnO4{-} + H{+} = Mn2{-} + CH3COOH + H2O =>
15 C2H5OH + 8 MnO4{-} + 4 H{+} = 4 Mn2{-} + 15 CH3COOH + 17 H2O

Cr2O7{-} + I{-} + H{+} = Cr3{+} + I2 + H2O =>
6 Cr2O7{-} + 74 I{-} + 84 H{+} = 4 Cr3{+} + 37 I2 + 42 H2O

Hg(OH)2 + H3AsO4 = Hg3(AsO4)2 + H2O =>
3 Hg(OH)2 + 2 H3AsO4 = Hg3(AsO4)2 + 6 H2O

Li2O + H2O = LiOH =>
Li2O + H2O = 2 LiOH

CH3CH2OH + K2Cr2O7 + H2SO4 = CH3COOH + Cr2(SO4)3 + K2SO4 + H2O =>
3 CH3CH2OH + 2 K2Cr2O7 + 8 H2SO4 = 3 CH3COOH + 2 Cr2(SO4)3 + 2 K2SO4 + 11 H2O

C2H5OH + MnO4{-} + H{+} = Mn2{+} + CH3COOH + H2O =>
13 C2H5OH + 8 MnO4{-} + 12 H{+} = 4 Mn2{+} + 13 CH3COOH + 19 H2O

NO + O2 = NO2 =>
2 NO + O2 = 2 NO2

Cr2O7{2-}{-} + I{-} + H{+} = Cr{3+} + I2 + H2O =>
Cr2O7{2-}{-} + 6 I{-} + 14 H{+} = 2 Cr{3+} + 3 I2 + 7 H2O

Na2HPO4 = Na4P2O7 + H2O =>
2 Na2HPO4 = Na4P2O7 + H2O

Cu + HNO3 = Cu(NO3)2 + NO + H2O =>
3 Cu + 8 HNO3 = 3 Cu(NO3)2 + 2 NO + 4 H2O

Al(s) + H2SO4(aq) = Al2(SO4)3(aq) + H2(g) =>
2 Al(s) + 3 H2SO4(aq) = Al2(SO4)3(aq) + 3 H2(g)

Na2HPO4 = Na4P2O7 + H2O =>
2 Na2HPO4 = Na4P2O7 + H2O

Fe2O3 + Al = Fe + Al2O3 =>
Fe2O3 + 2 Al = 2 Fe + Al2O3

C2H2(acetylene) + O2(oxygen) = CO + H20(water) =>
10 C2H2(acetylene) + 10 O2(oxygen) = 20 CO + H20(water)

C2H2(acetylene) + O2(oxygen) = CO + H20(water) =>
10 C2H2(acetylene) + 10 O2(oxygen) = 20 CO + H20(water)

C2H2(acetylene) + O2(oxygen) = CO + H20(water) =>
10 C2H2(acetylene) + 10 O2(oxygen) = 20 CO + H20(water)

C2H2(acetylene) + O2(oxygen) = CO + H20(water) =>
10 C2H2(acetylene) + 10 O2(oxygen) = 20 CO + H20(water)

C2H2(acetylene) + O2(oxygen) = CO + H20(water) =>
10 C2H2(acetylene) + 10 O2(oxygen) = 20 CO + H20(water)

NH3 + O2 = NO + H2O =>
4 NH3 + 5 O2 = 4 NO + 6 H2O

C2H2(acetylene) + O2(oxygen) = CO + H20(water) =>
10 C2H2(acetylene) + 10 O2(oxygen) = 20 CO + H20(water)

H4AS2O7 = AS2O5 + H2O =>
H4AS2O7 = AS2O5 + 2 H2O

H4AS2O7 = AS2O5 + H2O =>
H4AS2O7 = AS2O5 + 2 H2O

CaCO3 + C3H6O3 = CaC2H3O2 + H2O + CO2 =>
4 CaCO3 + 3 C3H6O3 = 4 CaC2H3O2 + 3 H2O + 5 CO2

CaCO3 + C3H6O3 = CaC2H3O2 + H2O + CO2 =>
4 CaCO3 + 3 C3H6O3 = 4 CaC2H3O2 + 3 H2O + 5 CO2

Na2CO3 + HCl = NaCl + H2O + CO2 =>
Na2CO3 + 2 HCl = 2 NaCl + H2O + CO2

SH{-} + H{+} = SH2 =>
SH{-} + H{+} = SH2

CaC2 + N2 = CaCN2 + C =>
CaC2 + N2 = CaCN2 + C

HgO = Hg + O2 =>
2 HgO = 2 Hg + O2

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Balance equation of any chemical reaction online for free
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