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Chemical Equations Balanced on 08/20/16

 Equations balanced on the previous day Equations balanced on the next day
Balance equation of any chemical reaction online for free
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C8H18 + O2 = CO2 + H2O =>
2 C8H18 + 25 O2 = 16 CO2 + 18 H2O

HCl + Ca(OH)2 = H2O + CaCl2 =>
2 HCl + Ca(OH)2 = 2 H2O + CaCl2

NaOH + (NH4)3PO4 = Na3PO4 + H2O + NH3 =>
3 NaOH + (NH4)3PO4 = Na3PO4 + 3 H2O + 3 NH3

Cu + H2SO4 = CuSO4 + SO2 + H2O =>
Cu + 2 H2SO4 = CuSO4 + SO2 + 2 H2O

BrF3 = Br2 + F2 =>
2 BrF3 = Br2 + 3 F2

N2 + H2 = NH3 =>
N2 + 3 H2 = 2 NH3

CH3CH3 + O2 = CO2 + H2O =>
2 CH3CH3 + 7 O2 = 4 CO2 + 6 H2O

Ca(OH)2 + H2SO4 = Ca(SO4) + H2O =>
Ca(OH)2 + H2SO4 = Ca(SO4) + 2 H2O

Mg + O2 = MgO =>
2 Mg + O2 = 2 MgO

HNO3 + HI = NO + I2 + H2O =>
2 HNO3 + 6 HI = 2 NO + 3 I2 + 4 H2O

BaO + H20 = BaOH2 =>
10 BaO + H20 = 10 BaOH2

CS2(l) + NH3(g) = H2S(g) + NH4SCN(s) =>
CS2(l) + 2 NH3(g) = H2S(g) + NH4SCN(s)

Fe + HC2H3O2 = Fe(C2H3O2)3 + H2 =>
2 Fe + 6 HC2H3O2 = 2 Fe(C2H3O2)3 + 3 H2

HNO3 + H2S = NO + S + H2O =>
2 HNO3 + 3 H2S = 2 NO + 3 S + 4 H2O

Na + Cl2 = NaCl =>
2 Na + Cl2 = 2 NaCl

C2H5OH + O2 = CO2 + H2O =>
C2H5OH + 3 O2 = 2 CO2 + 3 H2O

HNO3 + H2S = NO2 + H2O + S =>
2 HNO3 + H2S = 2 NO2 + 2 H2O + S

C4H10 + O2 = CO2 + H2 =>
C4H10 + 4 O2 = 4 CO2 + 5 H2

P2S3 + HIO3 + H2O = H3PO4 + S + HI =>
3 P2S3 + 5 HIO3 + 9 H2O = 6 H3PO4 + 9 S + 5 HI

Ca(OH)2 + H3PO4 = H2O + Ca3(PO4)2 =>
3 Ca(OH)2 + 2 H3PO4 = 6 H2O + Ca3(PO4)2

KMnO4 + HCl = KCl + MnCl2 + H2O + Cl2 =>
2 KMnO4 + 16 HCl = 2 KCl + 2 MnCl2 + 8 H2O + 5 Cl2

ZnCO3 + H3Po4 = Zn3(Po4)2 + H2O + CO2 =>
3 ZnCO3 + 2 H3Po4 = Zn3(Po4)2 + 3 H2O + 3 CO2

C4H10 + O2 = CO2 + H2O =>
2 C4H10 + 13 O2 = 8 CO2 + 10 H2O

Fe2O3 + C = Fe + CO2 =>
2 Fe2O3 + 3 C = 4 Fe + 3 CO2

CuS + HNO3 = Cu(NO3)2 + S + H2O + NO =>
3 CuS + 8 HNO3 = 3 Cu(NO3)2 + 3 S + 4 H2O + 2 NO

NaN3 + KNO3 + SiO2 = Na2SiO3 + K2SiO3 + N2 =>
10 NaN3 + 2 KNO3 + 6 SiO2 = 5 Na2SiO3 + K2SiO3 + 16 N2

S + O2 = SO3 =>
2 S + 3 O2 = 2 SO3

HCl + ZN(OH)2 = ZNCl2 + H2O =>
2 HCl + ZN(OH)2 = ZNCl2 + 2 H2O

Fe(NH4)2(SO4)2*6H2O + H2C2O4 + K2C2O4 + H2O2 = K3Fe(C2O4)3*3H2O + (NH4)2SO4 + H2SO4 + H2O =>
2 Fe(NH4)2(SO4)2*6H2O + 3 H2C2O4 + 3 K2C2O4 + H2O2 = 2 K3Fe(C2O4)3*3H2O + 2(NH4)2SO4 + 2 H2SO4 + 8 H2O

C8H18 + O2 = H2O + CO2 =>
2 C8H18 + 25 O2 = 18 H2O + 16 CO2

CrI3 + Cl2 + KOH = K2CrO4 + KIO3 + KCl + H2O =>
2 CrI3 + 21 Cl2 + 52 KOH = 2 K2CrO4 + 6 KIO3 + 42 KCl + 26 H2O

HgO = Hg + O2 =>
2 HgO = 2 Hg + O2

SO2 + O2 = SO3 =>
2 SO2 + O2 = 2 SO3

CO + O2 = CO2 =>
2 CO + O2 = 2 CO2

NaOH + H2So4 = Na2So4 + H2O =>
2 NaOH + H2So4 = Na2So4 + 2 H2O

H2O2 = H2O + O2 =>
2 H2O2 = 2 H2O + O2

CLO2 + KOH = KCL + KCLO3 + H2O =>
6 CLO2 + 6 KOH = KCL + 5 KCLO3 + 3 H2O

Cl2 + AgNO3 + H2O = AgCl + AgClO4 + HNO3 =>
4 Cl2 + 8 AgNO3 + 4 H2O = 7 AgCl + AgClO4 + 8 HNO3

KClO3 + NaI + HCl = KCl + NaCl + I2H2O =>
KClO3 + 6 NaI + 6 HCl = KCl + 6 NaCl + 3 I2H2O

KClO3 + NaI + HCl = KCl + NaCl + I2 + H2O =>
KClO3 + 6 NaI + 6 HCl = KCl + 6 NaCl + 3 I2 + 3 H2O

FeS + O2 = Fe2O3 + SO2 =>
4 FeS + 7 O2 = 2 Fe2O3 + 4 SO2

H2O = H2 + O2 =>
2 H2O = 2 H2 + O2

C2H5OH + O2 = CO2 + H2O =>
C2H5OH + 3 O2 = 2 CO2 + 3 H2O

Al + Cl2 = AlCl3 =>
2 Al + 3 Cl2 = 2 AlCl3

NH4 + Cl + NaOH = N2H4 + NaCl + H2O =>
2 NH4 + 4 Cl + 4 NaOH = N2H4 + 4 NaCl + 4 H2O

K2Cr2O3 + H2SO4 + O2 = KHSO4 + Cr2(SO4)3 + H2O =>
2 K2Cr2O3 + 10 H2SO4 + O2 = 4 KHSO4 + 2 Cr2(SO4)3 + 8 H2O

Pb(NO3)2 + K2Cr2O7 + CH3COONa + H2O = PbCrO4 + KNO3 + Na2CrO4 + CH3COOH =>
Pb(NO3)2 + K2Cr2O7 + 2 CH3COONa + H2O = PbCrO4 + 2 KNO3 + Na2CrO4 + 2 CH3COOH

Pb(NO3)2 + K2Cr2O7 + CH3COONa + H2O = PbCrO4 + KNO3 + Na2CrO4 + CH3COOH =>
Pb(NO3)2 + K2Cr2O7 + 2 CH3COONa + H2O = PbCrO4 + 2 KNO3 + Na2CrO4 + 2 CH3COOH

Pb(NO3)2 + K2Cr2O7 + CH3COONa + H2O = PbCrO4 + KNO3 + Na2CrO4 + CH3COOH =>
Pb(NO3)2 + K2Cr2O7 + 2 CH3COONa + H2O = PbCrO4 + 2 KNO3 + Na2CrO4 + 2 CH3COOH

Pb(NO3)2 + K2Cr2O7 + CH3COONa + H2O = PbCrO4 + KNO3 + Na2CrO4 + CH3COOH =>
Pb(NO3)2 + K2Cr2O7 + 2 CH3COONa + H2O = PbCrO4 + 2 KNO3 + Na2CrO4 + 2 CH3COOH

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Balance equation of any chemical reaction online for free
 Equations balanced on the previous day Equations balanced on the next day
Equations balanced on 08/13/16
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