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Chemical Equations Balanced on 09/01/17

 Equations balanced on the previous day Equations balanced on the next day
Balance equation of any chemical reaction online for free
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CaC2 + HNO3 = Ca(NO3)2 + C2H2 =>
CaC2 + 2 HNO3 = Ca(NO3)2 + C2H2

Br2 + HJ = HBr + J2 =>
Br2 + 2 HJ = 2 HBr + J2

FeS + O2 = Fe2O3 + SO2 =>
4 FeS + 7 O2 = 2 Fe2O3 + 4 SO2

BaCl2 + H2SO4 = HCl + BaSO4 =>
BaCl2 + H2SO4 = 2 HCl + BaSO4

CaC2 + HNO3 = Ca(NO3)2 + C2H2 =>
CaC2 + 2 HNO3 = Ca(NO3)2 + C2H2

Rb + RbNO3 = Rb2O + N3 =>
15 Rb + 3 RbNO3 = 9 Rb2O + N3

N2 + H2 = NH3 =>
N2 + 3 H2 = 2 NH3

FeS2 + O2 = Fe2O3 + SO2 =>
4 FeS2 + 11 O2 = 2 Fe2O3 + 8 SO2

KMNO4 + FeSO4 + H2SO4 = K2SO4 + MNSO4 + Fe2(SO4)3 + H2O =>
2 KMNO4 + 10 FeSO4 + 8 H2SO4 = K2SO4 + 2 MNSO4 + 5 Fe2(SO4)3 + 8 H2O

C2H4 + O2 = CO2 + H20 =>
5 C2H4 + 10 O2 = 10 CO2 + H20

Fe + C12 = FeC13 =>
12 Fe + 13 C12 = 12 FeC13

CaO + C = CaC2 + CO =>
CaO + 3 C = CaC2 + CO

Fe + C2 = FeC3 =>
2 Fe + 3 C2 = 2 FeC3

Li2CO3 + Ni(CH3COO)2*4H2O + (NH4)2HPO4 + Fe3O4 = LiNi001Fe099PO4 + NH3 + CO2 + H2O + O2 =>
Li2CO3 + 2 Ni(CH3COO)2*4H2O + 2(NH4)2HPO4 + 65.999999999999Fe3O4 = 2 LiNi001Fe099PO4 + 4 NH3 + 8.9999999999999CO2 + 17 H2O + 124 O2

Li2CO3 + (Ni(CH3COO)2)*4H2O + (NH4)2HPO4 + Fe3O4 = LiNi001Fe099PO4 + NH3 + CO2 + H2O + O2 =>
Li2CO3 + 2(Ni(CH3COO)2)*4H2O + 2(NH4)2HPO4 + 65.999999999999Fe3O4 = 2 LiNi001Fe099PO4 + 4 NH3 + 8.9999999999999CO2 + 17 H2O + 124 O2

Al + HBr = AlBr3 + H2 =>
2 Al + 6 HBr = 2 AlBr3 + 3 H2

[V(H2O)6] + O2 = V2O5 + H2O =>
4[V(H2O)6] + 5 O2 = 2 V2O5 + 24 H2O

N2 + H2 = NH3 =>
N2 + 3 H2 = 2 NH3

C8H18 + O2 = CO + H20 =>
10 C8H18 + 40 O2 = 80 CO + 9 H20

PbO2 + Mn(NO3)2 + HNO3 + KNO3 = KMnO4 + Pb(NO3)2 + H2O =>
5 PbO2 + 2 Mn(NO3)2 + 4 HNO3 + 2 KNO3 = 2 KMnO4 + 5 Pb(NO3)2 + 2 H2O

NH3(g) + CO2(g) = (NH2)2CO(ac) + H2O(l) =>
2 NH3(g) + CO2(g) = (NH2)2CO(ac) + H2O(l)

AlBr3 + F2 = AlF3 + Br2 =>
2 AlBr3 + 3 F2 = 2 AlF3 + 3 Br2

Cl2 + H2O = HCl + HClO3 =>
3 Cl2 + 3 H2O = 5 HCl + HClO3

FeO + H2O = Fe(OH)2 =>
FeO + H2O = Fe(OH)2

CACO3 = CAO + CO2 =>
CACO3 = CAO + CO2

Fe + H2O = Fe(OH)2 + H2 =>
Fe + 2 H2O = Fe(OH)2 + H2

LiOH + CO2 = LiCO3 + H20 =>
20 LiOH + 20 CO2 = 20 LiCO3 + H20

TiCl4(g) + Mg(l) = Ti(s) + MgCl2(l) =>
TiCl4(g) + 2 Mg(l) = Ti(s) + 2 MgCl2(l)

Cu(NO3)2 = CuO + NO2 + O2 =>
2 Cu(NO3)2 = 2 CuO + 4 NO2 + O2

Mg + O2 = MgO =>
2 Mg + O2 = 2 MgO

NaNO3 = NaNO2 + O2 =>
2 NaNO3 = 2 NaNO2 + O2

Al + O2 = Al2O3 =>
4 Al + 3 O2 = 2 Al2O3

C8H18 + O2 = C + H2O =>
2 C8H18 + 9 O2 = 16 C + 18 H2O

Li2CO3 + (Ni(CH3COO)2)*4H2O + (NH4)2HPO4 + Fe3O4 = LiNi001Fe099PO4 + NH3 + CO2 + H2O + O2 =>
Li2CO3 + 2(Ni(CH3COO)2)*4H2O + 2(NH4)2HPO4 + 65.999999999999Fe3O4 = 2 LiNi001Fe099PO4 + 4 NH3 + 8.9999999999999CO2 + 17 H2O + 124 O2

C2H2Cl4 + Ca(OH)2 = CaCl2 + H2O + C2HCl3 =>
2 C2H2Cl4 + Ca(OH)2 = CaCl2 + 2 H2O + 2 C2HCl3

HBrO4 + Zn(OH)2 = Zn(BrO4)2 + H2O =>
2 HBrO4 + Zn(OH)2 = Zn(BrO4)2 + 2 H2O

CH4S + O2 = C2H6S2 + H2O =>
4 CH4S + O2 = 2 C2H6S2 + 2 H2O

P + O2 = P2O3 =>
4 P + 3 O2 = 2 P2O3

Zn + H2SO4 + Ag3AsO4 = AsH3 + Ag + ZnSO4 + H2O =>
11 Zn + 11 H2SO4 + 2 Ag3AsO4 = 2 AsH3 + 6 Ag + 11 ZnSO4 + 8 H2O

Ca5(PO4)3F(s) + H2SO4(ac) = Ca(H2PO4)2(ac) + CaSO4(ac) + HF(g) =>
2 Ca5(PO4)3F(s) + 7 H2SO4(ac) = 3 Ca(H2PO4)2(ac) + 7 CaSO4(ac) + 2 HF(g)

KI + H2SO4 = H2S + I2 + K2SO4 + H2O =>
8 KI + 5 H2SO4 = H2S + 4 I2 + 4 K2SO4 + 4 H2O

BaO4 + HNO3 = Ba(NO3)2 + H2O2 + O2 =>
BaO4 + 2 HNO3 = Ba(NO3)2 + H2O2 + O2

BaO4 + HNO3 = Ba(NO3)2 + H2O2 + O2 =>
BaO4 + 2 HNO3 = Ba(NO3)2 + H2O2 + O2

CO + NO = CO2 + N2 =>
2 CO + 2 NO = 2 CO2 + N2

Cr(OH)4{-} + Na2O2 = CrO4{-2} + Na{+} + OH{-} + H2O =>
2 Cr(OH)4{-} + 3 Na2O2 = 2 CrO4{-2} + 6 Na{+} + 4 OH{-} + 2 H2O

HCl + Na3AsO3 = NaCl + H3AsO3 =>
3 HCl + Na3AsO3 = 3 NaCl + H3AsO3

N2H2 = N2 + NH3 =>
3 N2H2 = 2 N2 + 2 NH3

NO2 + H2O = HNO3 + NO =>
3 NO2 + H2O = 2 HNO3 + NO

N2 + H2 = NH3 =>
N2 + 3 H2 = 2 NH3

N2H2 = N2 + NH3 =>
3 N2H2 = 2 N2 + 2 NH3

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Balance equation of any chemical reaction online for free
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