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Chemical Equations Balanced on 12/22/18

 Equations balanced on the previous day Equations balanced on the next day
Balance equation of any chemical reaction online for free
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NH3 + O = NO + H2O =>
2 NH3 + 5 O = 2 NO + 3 H2O

Zn + H2SO4 = Zn(SO4) + H2 =>
Zn + H2SO4 = Zn(SO4) + H2

MnO2 + O2 + KOH = K2MnO4 + H2O =>
2 MnO2 + O2 + 4 KOH = 2 K2MnO4 + 2 H2O

Zn + H2SO4 = Zn(SO3) + H2O =>
Zn + H2SO4 = Zn(SO3) + H2O

SO3 + BA(OH)2 = BASO4 + H2O =>
SO3 + BA(OH)2 = BASO4 + H2O

C3H8 + Br = C3H6Br + H2 =>
C3H8 + Br = C3H6Br + H2

C20H41OH + O2 = CO2 + H2O =>
C20H41OH + 30 O2 = 20 CO2 + 21 H2O

FeS2 + O2 = Fe2O3 + S02 =>
4 FeS2 + 3 O2 = 2 Fe2O3 + 4 S02

FeS2 + K2MnO4 + KHSO4 = Fe2(SO4)3 + MnSO4 + K2SO4 + H2O =>
4 FeS2 + 15 K2MnO4 + 56 KHSO4 = 2 Fe2(SO4)3 + 15 MnSO4 + 43 K2SO4 + 28 H2O

C3H8O3 + O2 = CO2 + H2O =>
2 C3H8O3 + 7 O2 = 6 CO2 + 8 H2O

SiO2 + C = Si + CO =>
SiO2 + 2 C = Si + 2 CO

C2H2 + [Cu(NH3)4]Cl = C2Cu2 + NH3 + HCl =>
C2H2 + 2[Cu(NH3)4]Cl = C2Cu2 + 8 NH3 + 2 HCl

Al + CuCl2 = AlCl3 + Cu =>
2 Al + 3 CuCl2 = 2 AlCl3 + 3 Cu

Li + H2CO3 = LiCO3 + H2 =>
Li + H2CO3 = LiCO3 + H2

Cl2 + Al = AlCl3 =>
3 Cl2 + 2 Al = 2 AlCl3

Al + CuCl2 = AlCl3 + Cu =>
2 Al + 3 CuCl2 = 2 AlCl3 + 3 Cu

Al + CuCl2 = AlCl3 + Cu =>
2 Al + 3 CuCl2 = 2 AlCl3 + 3 Cu

Zn + H2SO4 = Zn2SO4 + H2 =>
2 Zn + H2SO4 = Zn2SO4 + H2

H{+} + MnO4{-} + Cl{-} = Mn{+2} + Cl2 + H2O =>
16 H{+} + 2 MnO4{-} + 10 Cl{-} = 2 Mn{+2} + 5 Cl2 + 8 H2O

CH3CH(NH2)COOH + HBr = CH3CHBrCOOH + NH3 =>
CH3CH(NH2)COOH + HBr = CH3CHBrCOOH + NH3

C5H10O5 = CO2 + CH4 =>
2 C5H10O5 = 5 CO2 + 5 CH4

Al + H2So4 = Al2(So4)3 + H2 =>
2 Al + 3 H2So4 = Al2(So4)3 + 3 H2

NaJ + KMnO4 + KOH = J2 + K2MnO4 + NaOH =>
2 NaJ + 2 KMnO4 + 2 KOH = J2 + 2 K2MnO4 + 2 NaOH

HCl + Mg = MgCl2 + H2 =>
2 HCl + Mg = MgCl2 + H2

BaBr2 + Na2So4 = BaSo4 + NaBr =>
BaBr2 + Na2So4 = BaSo4 + 2 NaBr

C3H6 + O2 = H2O + CO2 =>
2 C3H6 + 9 O2 = 6 H2O + 6 CO2

C6H8O7H20 + Cu(N03)225H20 + Fe(NO3)39H20 = CuFe2O4 + H20 + CO2 + N2 =>
460 C6H8O7H20 + 10 Cu(N03)225H20 + 20 Fe(NO3)39H20 = 10 CuFe2O4 + 674 H20 + 2760 CO2 + 3765 N2

H{+} + MnO4{-} + Cl{-} = Mn{+2} + Cl2 + H2O =>
16 H{+} + 2 MnO4{-} + 10 Cl{-} = 2 Mn{+2} + 5 Cl2 + 8 H2O

C6H8O7H2O + Cu(N03)225H20 + Fe(NO3)39H20 = CuFe2O4 + H20 + CO2 + N2 =>
230 C6H8O7H2O + 4 Cu(N03)225H20 + 8 Fe(NO3)39H20 = 4 CuFe2O4 + 127 H20 + 1380 CO2 + 1506 N2

C3H4 + O2 = H2O + CO2 =>
C3H4 + 4 O2 = 2 H2O + 3 CO2

K2Cr2O7 + H2SO4 = K2SO4 + Cr2(SO4)3 + H2O + O3 =>
K2Cr2O7 + 4 H2SO4 = K2SO4 + Cr2(SO4)3 + 4 H2O + O3

Fe2(SO4)3 = Fe + O2 + SO3 =>
2 Fe2(SO4)3 = 4 Fe + 3 O2 + 6 SO3

C3H8 + O2 = H2O + CO2 =>
C3H8 + 5 O2 = 4 H2O + 3 CO2

K2Cr2O7 + H2SO4 = K2SO4 + Cr2(SO4)3 + H2O + O2 =>
2 K2Cr2O7 + 8 H2SO4 = 2 K2SO4 + 2 Cr2(SO4)3 + 8 H2O + 3 O2

ZnSO4 + KOH = K2SO4 + Zn(OH)2 =>
ZnSO4 + 2 KOH = K2SO4 + Zn(OH)2

C3H7 + O2 = H2O + CO2 =>
4 C3H7 + 19 O2 = 14 H2O + 12 CO2

Cu + HNO3 = Cu(NO3)2 + NO2 + H2O =>
Cu + 4 HNO3 = Cu(NO3)2 + 2 NO2 + 2 H2O

C6H8O7H2O + Cu(N03)23H20 + Fe(NO3)39H20 = CuFe2O4 + H20 + CO2 + N2 =>
230 C6H8O7H2O + 4 Cu(N03)23H20 + 8 Fe(NO3)39H20 = 4 CuFe2O4 + 127 H20 + 1380 CO2 + 294 N2

KMnO4 + SnSO4 + H2SO4 = Sn(SO4)2 + MnSO4 + K2SO4 + H2O =>
2 KMnO4 + 5 SnSO4 + 8 H2SO4 = 5 Sn(SO4)2 + 2 MnSO4 + K2SO4 + 8 H2O

H2 + O2 = H2O =>
2 H2 + O2 = 2 H2O

C6H8O7 + Cu(N03)23H20 + Fe(NO3)39H20 = CuFe2O4 + H20 + CO2 + N2 =>
460 C6H8O7 + 10 Cu(N03)23H20 + 20 Fe(NO3)39H20 = 10 CuFe2O4 + 214 H20 + 2760 CO2 + 735 N2

ZnS + O2 = ZnO + SO2 =>
2 ZnS + 3 O2 = 2 ZnO + 2 SO2

HCOOH + Br2 = HBr + CO2 =>
HCOOH + Br2 = 2 HBr + CO2

NaBr + Cl2 = NaCl + Br2 =>
2 NaBr + Cl2 = 2 NaCl + Br2

C6H5C2H5 + Br2 = C6H5C2H4Br + HBr =>
C6H5C2H5 + Br2 = C6H5C2H4Br + HBr

K2Cr2O7 + HCl = KCl + CrCl + H2O + Cl2 =>
K2Cr2O7 + 14 HCl = 2 KCl + 2 CrCl + 7 H2O + 5 Cl2

PbCl2 + Na2S = PbS + NaCl =>
PbCl2 + Na2S = PbS + 2 NaCl

Fe + H2O = Fe3O4 + H2 =>
3 Fe + 4 H2O = Fe3O4 + 4 H2

N2O5 = NO2 + O2 =>
2 N2O5 = 4 NO2 + O2

C6H8O7 + Cu(N03)23H20 + Fe(NO3)39H20 = CuFe2O4 + H20 + CO2 + N2 =>
460 C6H8O7 + 10 Cu(N03)23H20 + 20 Fe(NO3)39H20 = 10 CuFe2O4 + 214 H20 + 2760 CO2 + 735 N2

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Balance equation of any chemical reaction online for free
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Equations balanced on 12/15/18
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