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Chemical Equations Balanced on 12/24/19

 Equations balanced on the previous day Equations balanced on the next day
Balance equation of any chemical reaction online for free
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NaOH(aq) + CaCl2(aq) = Ca(OH)2 + NaCl =>
2 NaOH(aq) + CaCl2(aq) = Ca(OH)2 + 2 NaCl

C5H11SO2N + O2 = CO2 + H2O + SO2 + NO2 =>
4 C5H11SO2N + 35 O2 = 20 CO2 + 22 H2O + 4 SO2 + 4 NO2

Al + Fe3O4 = Al2O3 + Fe =>
8 Al + 3 Fe3O4 = 4 Al2O3 + 9 Fe

Al + Fe3O4 = Al2O3 + Fe =>
8 Al + 3 Fe3O4 = 4 Al2O3 + 9 Fe

Al + Fe3O4 = Al2O3 + Fe =>
8 Al + 3 Fe3O4 = 4 Al2O3 + 9 Fe

C3H8 + O2 = CO2 + H2O =>
C3H8 + 5 O2 = 3 CO2 + 4 H2O

Ca(OH)2 + C4H6O5 = H2O + CaC4H4O5 =>
Ca(OH)2 + C4H6O5 = 2 H2O + CaC4H4O5

FeTiO3 + Cl2 + C = TiCl4 + FeCl3 + CO =>
2 FeTiO3 + 7 Cl2 + 6 C = 2 TiCl4 + 2 FeCl3 + 6 CO

C3H8 + O2 = CO2 + H2O =>
C3H8 + 5 O2 = 3 CO2 + 4 H2O

NH4OH + H2SO4 = (NH4)2SO4 + HOH =>
2 NH4OH + H2SO4 = (NH4)2SO4 + 2 HOH

H2CO3 + NH4OH = (NH4)2CO3 + HOH =>
H2CO3 + 2 NH4OH = (NH4)2CO3 + 2 HOH

ClO2{-} + S4O6{-2} + H2O = Cl{-} + SO4{-2} + H{+} =>
7 ClO2{-} + 2 S4O6{-2} + 6 H2O = 7 Cl{-} + 8 SO4{-2} + 12 H{+}

NaNH2 + NaNO3 = NaN3 + NaOH + NH3 =>
3 NaNH2 + NaNO3 = NaN3 + 3 NaOH + NH3

ZnO + HCl = ZnCl2 + H2O =>
ZnO + 2 HCl = ZnCl2 + H2O

CO(NH2)2 + HOCl = NCl3 + CO2 + H2O =>
CO(NH2)2 + 6 HOCl = 2 NCl3 + CO2 + 5 H2O

H2 + Cl2 = HCl =>
H2 + Cl2 = 2 HCl

ZnCl2 + NaCN = Zn(CN)2 + NaCl =>
ZnCl2 + 2 NaCN = Zn(CN)2 + 2 NaCl

FeCl3*6H2O + KIO3 = Fe(IO3)3 + KCl + H2O =>
FeCl3*6H2O + 3 KIO3 = Fe(IO3)3 + 3 KCl + 6 H2O

C3H8 + O2 = CO2 + H3O =>
3 C3H8 + 13 O2 = 9 CO2 + 8 H3O

CO(NH2)2 + NaNO3 + HCl = NaCl + H2O + CO2 + N2 =>
5 CO(NH2)2 + 6 NaNO3 + 6 HCl = 6 NaCl + 13 H2O + 5 CO2 + 8 N2

NaNo3 + PBO = PB(No3)2 + Na2O =>
2 NaNo3 + PBO = PB(No3)2 + Na2O

Pb(NO3)2 + NaI = PbI2 + NaNO3 =>
Pb(NO3)2 + 2 NaI = PbI2 + 2 NaNO3

C3H8 + O2 = CO2 + H2O =>
C3H8 + 5 O2 = 3 CO2 + 4 H2O

CO(NH2)2 + NaNO2 + HCl = NaCl + H2O + CO2 + N2 =>
CO(NH2)2 + 2 NaNO2 + 2 HCl = 2 NaCl + 3 H2O + CO2 + 2 N2

C3H8 + O2 = CO2 + H2O =>
C3H8 + 5 O2 = 3 CO2 + 4 H2O

BrO3{-} + S4O6{-2} + H2O = Br{-} + SO4{-2} + H{+} =>
7 BrO3{-} + 3 S4O6{-2} + 9 H2O = 7 Br{-} + 12 SO4{-2} + 18 H{+}

TiO2 + CO + Cl2 = TiCl4 + CO2 =>
TiO2 + 2 CO + 2 Cl2 = TiCl4 + 2 CO2

SO2 + Na2Cr2O7 + H2SO4 = Na2SO4 + Cr2(SO4)3 + H2O =>
3 SO2 + Na2Cr2O7 + H2SO4 = Na2SO4 + Cr2(SO4)3 + H2O

Ce{4+} + As{3+} = Ce{3+} + As{5+} =>
2 Ce{4+} + As{3+} = 2 Ce{3+} + As{5+}

K(s) + ZnCl2(aq) = KCl2 + Zn =>
K(s) + ZnCl2(aq) = KCl2 + Zn

H2SO4 + B(OH)3 = B2(SO4)3 + H2O =>
3 H2SO4 + 2 B(OH)3 = B2(SO4)3 + 6 H2O

Cu + HNO3 = Cu(NO3)2 + NO2 + H2O =>
Cu + 4 HNO3 = Cu(NO3)2 + 2 NO2 + 2 H2O

ZnSO4 + NaCN = Zn(CN)2 + Na2SO4 =>
ZnSO4 + 2 NaCN = Zn(CN)2 + Na2SO4

FeS2 + O2 = Fe2O3 + SO2 =>
4 FeS2 + 11 O2 = 2 Fe2O3 + 8 SO2

SO2 + O2 = SO3 =>
2 SO2 + O2 = 2 SO3

Al(NO3)3 + Na2S = Al2S3 + NaNO3 =>
2 Al(NO3)3 + 3 Na2S = Al2S3 + 6 NaNO3

H2 + Cl2 = HCl =>
H2 + Cl2 = 2 HCl

Al(OH)3 + NaOH = Na3AlO3 + H2O =>
Al(OH)3 + 3 NaOH = Na3AlO3 + 3 H2O

Ce{4+} + (COO)2{2-} = Ce{3+} + CO2 =>
2 Ce{4+} + (COO)2{2-} = 2 Ce{3+} + 2 CO2

KJ + KMnO4 + H2SO4 = J2 + K2SO4 + MnSO4 + H2O =>
10 KJ + 2 KMnO4 + 8 H2SO4 = 5 J2 + 6 K2SO4 + 2 MnSO4 + 8 H2O

KMnO4 + HCl + H2S = KCl + MnCl2 + S + H2O =>
2 KMnO4 + 6 HCl + 5 H2S = 2 KCl + 2 MnCl2 + 5 S + 8 H2O

AlP + Na = Na3P + Al =>
AlP + 3 Na = Na3P + Al

NaClO + NaI + H2SO4 = I2 + NaCl + Na2SO4 + H2O =>
NaClO + 2 NaI + H2SO4 = I2 + NaCl + Na2SO4 + H2O

Al(NO3)3 + H2SO4 = Al2(SO4)3 + HNO3 =>
2 Al(NO3)3 + 3 H2SO4 = Al2(SO4)3 + 6 HNO3

Br2 + S{-2} + H2O = Br{-} + SO4{-2} + H{+} =>
4 Br2 + S{-2} + 4 H2O = 8 Br{-} + SO4{-2} + 8 H{+}

H3PO4 + NaOH = NaH2PO4 + H2O =>
H3PO4 + NaOH = NaH2PO4 + H2O

C2H5OH + O2 = CO2 + H2O =>
C2H5OH + 3 O2 = 2 CO2 + 3 H2O

Zn + CuCl2 = ZnCl2 + Cu =>
Zn + CuCl2 = ZnCl2 + Cu

MgO + CaS = MgS + CaO =>
MgO + CaS = MgS + CaO

CH3OH + O2 = CO2 + H2O =>
2 CH3OH + 3 O2 = 2 CO2 + 4 H2O

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Balance equation of any chemical reaction online for free
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Equations balanced on 12/17/19
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Equations balanced on 12/24/18
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