Equations balanced on the previous day | Equations balanced on the next day |
61 Ce(NO3)4 + K4[Fe(CN)6] + 258 KOH = 61 Ce(OH)3 + Fe(OH)3 + 250 KNO3 + 6 K2CO3 + 36 H2O
Fe2O3 + HCe = FeCe3 + H2O =>
Fe2O3 + 6 HCe = 2 FeCe3 + 3 H2O
ZnI2 + K2(CO3) = Zn(CO3) + KI =>
ZnI2 + K2(CO3) = Zn(CO3) + 2 KI
CH3CH2CH2OH + CuO = Cu + CH3CH2CH2O + H2O =>
2 CH3CH2CH2OH + CuO = Cu + 2 CH3CH2CH2O + H2O
Ni{2+} + H2D = Ni(D)2 + H{+} + H2 =>
Ni{2+} + 2 H2D = Ni(D)2 + 2 H{+} + H2
KHCO3(s) + HCl(aq) = KCl(aq) + H2O(l) + CO2 =>
KHCO3(s) + HCl(aq) = KCl(aq) + H2O(l) + CO2
CaSO4 + C = CaO + SO2 + CO2 =>
2 CaSO4 + C = 2 CaO + 2 SO2 + CO2
Hg{2+} + Sn{2+} = Hg + Sn{4+} =>
Hg{2+} + Sn{2+} = Hg + Sn{4+}
Co(NH3)6 + HC2H3O2(aq) = Co + NH4C2H3O2 =>
Co(NH3)6 + 6 HC2H3O2(aq) = Co + 6 NH4C2H3O2
Al + NaBO3 + H2O = NaAlO3 + B2O3 + H2 =>
2 Al + 2 NaBO3 + 3 H2O = 2 NaAlO3 + B2O3 + 3 H2
C6H6 + H2O2 = C6H5O + H2O =>
2 C6H6 + 3 H2O2 = 2 C6H5O + 4 H2O
ZnI2 + K2(CO3) = Zn(CO3) + KI =>
ZnI2 + K2(CO3) = Zn(CO3) + 2 KI
NaOH + H2CO3 = CO3 + H2O + Na =>
2 NaOH + H2CO3 = CO3 + 2 H2O + 2 Na
C6H6 + H2O2 = C6H5O + H2O =>
2 C6H6 + 3 H2O2 = 2 C6H5O + 4 H2O
C6H6 + H2O2 = C6H5O + H2O =>
2 C6H6 + 3 H2O2 = 2 C6H5O + 4 H2O
N2(g) + H2(g) = NH4(g) =>
N2(g) + 4 H2(g) = 2 NH4(g)
CdCl2 + K2S = K2Cl2 + CdS =>
CdCl2 + K2S = K2Cl2 + CdS
Ni{2+} + H2D = Ni(D)2 + H{+} + H2 =>
Ni{2+} + 2 H2D = Ni(D)2 + 2 H{+} + H2
Na2(SO4) + CsNO3 = Cs2(SO4) + NaNO3 =>
Na2(SO4) + 2 CsNO3 = Cs2(SO4) + 2 NaNO3
KBr + Cl3 + KOH = KCl + KBrO3 + H2O =>
KBr + 2 Cl3 + 6 KOH = 6 KCl + KBrO3 + 3 H2O
NaHCO3 = CNa2O3 + H2O + CO2 =>
2 NaHCO3 = CNa2O3 + H2O + CO2
Jr + H2O = H2 + Jr(OH) =>
2 Jr + 2 H2O = H2 + 2 Jr(OH)
Bi(OH)3 + HCl = BiOHCl2 + H2O =>
Bi(OH)3 + 2 HCl = BiOHCl2 + 2 H2O
CdCl2 + K2S = K2Cl2 + CdS =>
CdCl2 + K2S = K2Cl2 + CdS
Jr + H2O = H2 + Jr(OH) =>
2 Jr + 2 H2O = H2 + 2 Jr(OH)
CuCl + HNO3 = Cl2 + Cu(NO3)2 + NO2 + H2O =>
2 CuCl + 8 HNO3 = Cl2 + 2 Cu(NO3)2 + 4 NO2 + 4 H2O
C6H6 + H2O2 = C6H5O + H2O =>
2 C6H6 + 3 H2O2 = 2 C6H5O + 4 H2O
Ce(NO3)4 + K4[Fe(CN)6] + KOH = Ce(OH)3 + Fe(OH)3 + KNO3 + K2CO3 + H2O =>
61 Ce(NO3)4 + K4[Fe(CN)6] + 258 KOH = 61 Ce(OH)3 + Fe(OH)3 + 250 KNO3 + 6 K2CO3 + 36 H2O
NaCaCO3 + C3H5O = NaCaCO + CO2 + H2O =>
15 NaCaCO3 + 4 C3H5O = 15 NaCaCO + 12 CO2 + 10 H2O
Fe2O3 + HCe = FeCe3 + H2O =>
Fe2O3 + 6 HCe = 2 FeCe3 + 3 H2O
C6H6 + H2O2 = C6H5O + H2O =>
2 C6H6 + 3 H2O2 = 2 C6H5O + 4 H2O
Ni{2+} + H2D = Ni(D)2 + H{+} + H2 =>
Ni{2+} + 2 H2D = Ni(D)2 + 2 H{+} + H2
Co(NH3)6 + HC2H3O2(aq) = Co + NH4C2H3O2 =>
Co(NH3)6 + 6 HC2H3O2(aq) = Co + 6 NH4C2H3O2
Ni{2+} + H2D = Ni(D)2 + H{+} + H2 =>
Ni{2+} + 2 H2D = Ni(D)2 + 2 H{+} + H2
Mg + HNO3 = N2O + MgNO3 + H2O =>
8 Mg + 10 HNO3 = N2O + 8 MgNO3 + 5 H2O
CdCl2 + K2S = K2Cl2 + CdS =>
CdCl2 + K2S = K2Cl2 + CdS
ClO3({-}1) + HNO2 = Cl2 + NO3({-}1) + H{+} + H2O =>
2 ClO3({-}1) + 5 HNO2 = Cl2 + 5 NO3({-}1) + 3 H{+} + H2O
CH3COOCH7 + O2 = CO2 + H2O =>
2 CH3COOCH7 + 9 O2 = 6 CO2 + 10 H2O
CaCl2(aq) + NaCO3(aq) = Ca(CO3)2 + NaCl =>
CaCl2(aq) + 2 NaCO3(aq) = Ca(CO3)2 + 2 NaCl
Co(NH3)6 + HC2H3O2(aq) = Co + NH4C2H3O2 =>
Co(NH3)6 + 6 HC2H3O2(aq) = Co + 6 NH4C2H3O2
Ce(NO3)4 + K4[Fe(CN)6] + KOH = Ce(OH)3 + Fe(OH)3 + KNO3 + K2CO3 + H2O =>
61 Ce(NO3)4 + K4[Fe(CN)6] + 258 KOH = 61 Ce(OH)3 + Fe(OH)3 + 250 KNO3 + 6 K2CO3 + 36 H2O
FeSO4 + H2 = Fe + H2S + H2O =>
FeSO4 + 5 H2 = Fe + H2S + 4 H2O
Jr + H2O = H2 + Jr(OH) =>
2 Jr + 2 H2O = H2 + 2 Jr(OH)
ZnI2 + K2(CO3) = Zn(CO3) + KI =>
ZnI2 + K2(CO3) = Zn(CO3) + 2 KI
Ba + NO2 = BaO + N2 =>
4 Ba + 2 NO2 = 4 BaO + N2
NaOH + H2CO3 = CO3 + H2O + Na =>
2 NaOH + H2CO3 = CO3 + 2 H2O + 2 Na
Cu7P + HCl + H2O2 = CuCl + H3PO4 + H =>
Cu7P + 7 HCl + 2 H2O2 = 7 CuCl + H3PO4 + 8 H
NaOH + H2CO3 = CO3 + H2O + Na =>
2 NaOH + H2CO3 = CO3 + 2 H2O + 2 Na
*C3H8 + O2 = CO2 + H2O =>
*C3H8 + 5 O2 = 3 CO2 + 4 H2O
Fe2O3 + HCe = FeCe3 + H2O =>
Fe2O3 + 6 HCe = 2 FeCe3 + 3 H2O
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 11/18/23
Equations balanced on 12/18/22
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