Equations balanced on the previous day | Equations balanced on the next day |
4 C8H11O + 41 O2 = 32 CO2 + 22 H2O
CuSO4 + SnCl2 = CuCl2 + SnSO4 =>
CuSO4 + SnCl2 = CuCl2 + SnSO4
KOH + Na2S2O3 = K2S2O3 + NaOH =>
2 KOH + Na2S2O3 = K2S2O3 + 2 NaOH
H2SO4 + C = CO2 + SO2 + H2O =>
2 H2SO4 + C = CO2 + 2 SO2 + 2 H2O
C2H(OH) + O2 = CO2 + H2O =>
C2H(OH) + 2 O2 = 2 CO2 + H2O
(CH2)2NH2COOH + O2 = CO2 + H2O + N2 =>
4(CH2)2NH2COOH + 15 O2 = 12 CO2 + 14 H2O + 2 N2
FeSO4 + KClO3 + H2SO4 = K2SO4 + Fe2(SO4)3 + H2O + Cl2 =>
10 FeSO4 + 2 KClO3 + 6 H2SO4 = K2SO4 + 5 Fe2(SO4)3 + 6 H2O + Cl2
Al(OH)3 + CaCl = Al2Cl3 + Ca(OH)2 =>
2 Al(OH)3 + 3 CaCl = Al2Cl3 + 3 Ca(OH)2
AgCl(s) + H2S(aq) = HCl(s) + Ag2S(g) =>
2 AgCl(s) + H2S(aq) = 2 HCl(s) + Ag2S(g)
KNO2 + KMnO4 + H2O = MnO2 + HNO3 + KOH =>
3 KNO2 + 2 KMnO4 + 4 H2O = 2 MnO2 + 3 HNO3 + 5 KOH
Al + KOH + H2O = K[Al(OH)]4 + H2 =>
8 Al + 2 KOH + 6 H2O = 2 K[Al(OH)]4 + 3 H2
Cu{2}(aq) + Mg(s) = Cu(s) + Mg{2}(aq) =>
Cu{2}(aq) + Mg(s) = Cu(s) + Mg{2}(aq)
Zn + V{5+} = Zn{2+} + V{2+} =>
3 Zn + 2 V{5+} = 3 Zn{2+} + 2 V{2+}
K2Cr2O7(aq) + HBr(aq) = KBr(aq) + CrBr3(aq) + H2O(l) + Br2(g) =>
K2Cr2O7(aq) + 14 HBr(aq) = 2 KBr(aq) + 2 CrBr3(aq) + 7 H2O(l) + 3 Br2(g)
HBrO + Mo(OH)6 = Mo(OH)3 + (BrO)3 + H2O =>
3 HBrO + Mo(OH)6 = Mo(OH)3 + (BrO)3 + 3 H2O
Na3[Cr(OH)6] + H2SO4 = Cr2(SO4)3 + H2O + NaOH =>
2 Na3[Cr(OH)6] + 3 H2SO4 = Cr2(SO4)3 + 6 H2O + 6 NaOH
SrCO3 + Nd2O3 + H3BO3 = Sr4NdO(BO3)3 + H2O + CO2 =>
8 SrCO3 + Nd2O3 + 6 H3BO3 = 2 Sr4NdO(BO3)3 + 9 H2O + 8 CO2
Pd(OH) + NO3 = Pd(OH)NO3 =>
Pd(OH) + NO3 = Pd(OH)NO3
Cu{2}Cl + Fe = Fe{3} + Cu =>
3 Cu{2}Cl + 2 Fe = 2 Fe{3} + 3 Cu
H4As2O9 + Be(OH)2 = Be2(As2O9) + H2O =>
H4As2O9 + 2 Be(OH)2 = Be2(As2O9) + 4 H2O
PCl3 + NH3 = P(NH2)3 + HCl =>
PCl3 + 3 NH3 = P(NH2)3 + 3 HCl
K2SO4 + Ba(NO3)2 = BaSO4 + K2(NO3)2 =>
K2SO4 + Ba(NO3)2 = BaSO4 + K2(NO3)2
H3PO3 + Hg(NO3)2 = H3PO4 + Hg + NO =>
4 H3PO3 + Hg(NO3)2 = 4 H3PO4 + Hg + 2 NO
C4H10S(l) + O2(g) = SO4(g) + H2O(g) + CO2(g) =>
2 C4H10S(l) + 17 O2(g) = 2 SO4(g) + 10 H2O(g) + 8 CO2(g)
Mn2O7 + NaOH = Na2Mn2O8 + H2O =>
Mn2O7 + 2 NaOH = Na2Mn2O8 + H2O
FeO + PbO = Fe + PbO2 =>
FeO + PbO = Fe + PbO2
CaO + H2O = Ca(OH)2 =>
CaO + H2O = Ca(OH)2
N3{-} + Cu2{+} = Cu + N2 =>
2 N3{-} + 2 Cu2{+} = 4 Cu + 3 N2
CH3COOH + CaMg(CO3)2 = (CH3COO)2Ca + (CH3COO)2Mg + CO2 + H2O =>
4 CH3COOH + CaMg(CO3)2 = (CH3COO)2Ca + (CH3COO)2Mg + 2 CO2 + 2 H2O
C5H5N + O2 = CO2 + H2O + NO2 =>
4 C5H5N + 29 O2 = 20 CO2 + 10 H2O + 4 NO2
KOH(aq) + CuSO4(s) = Cu(OH)2(aq) + K2SO4(s) =>
2 KOH(aq) + CuSO4(s) = Cu(OH)2(aq) + K2SO4(s)
CH4 = H + C =>
CH4 = 4 H + C
Mg8H16 + Ni = NiMg7H16 + Mg =>
Mg8H16 + Ni = NiMg7H16 + Mg
HBr + Ca(OH)2 = HOH + CaBr2 =>
2 HBr + Ca(OH)2 = 2 HOH + CaBr2
Mg{2+} + EDTA{4-} = Mg2EDTA =>
2 Mg{2+} + EDTA{4-} = Mg2EDTA
K2Cr2O7 + C3H7OH = C2H5COOH + Cr2O3 + KOH + H2O =>
2 K2Cr2O7 + 3 C3H7OH = 3 C2H5COOH + 2 Cr2O3 + 4 KOH + H2O
CH3CH2CH3(g) + O2 = CO2 + H2O(g) =>
CH3CH2CH3(g) + 5 O2 = 3 CO2 + 4 H2O(g)
*2N2 + H2 = NH3 =>
*2N2 + 6 H2 = 4 NH3
Cr4N48H96C24O24Cr3C18N18 + KMnO4 + H2SO4 = K2Cr2O7 + MnSO4 + CO2 + KNO3 + K2SO4 + H2O =>
10 Cr4N48H96C24O24Cr3C18N18 + 1176 KMnO4 + 1399 H2SO4 = 35 K2Cr2O7 + 1176 MnSO4 + 420 CO2 + 660 KNO3 + 223 K2SO4 + 1879 H2O
Rb(s) + S(s) = Rb2S(s) =>
2 Rb(s) + S(s) = Rb2S(s)
(NH4)2SO4 + NaCl = (NH4)2Cl + SO4Na =>
(NH4)2SO4 + NaCl = (NH4)2Cl + SO4Na
Na2S + Bi(NO3)3 = Bi2S3 + Na{+]+NO3{-} =>
3 Na2S + 2 Bi(NO3)3 = Bi2S3 + 6 Na{+]+6NO3{-}
CoCl2*6H2O + NH3 + H2O2 + NH4Cl = [Co(NH3)5Cl]Cl2 + H2O =>
2 CoCl2*6H2O + 8 NH3 + H2O2 + 2 NH4Cl = 2[Co(NH3)5Cl]Cl2 + 14 H2O
C8H5O4K(aq) + NaOH(aq) = Na(aq) + K(aq) + C8H4O4(aq) + H2O(l) =>
C8H5O4K(aq) + NaOH(aq) = Na(aq) + K(aq) + C8H4O4(aq) + H2O(l)
CuCl2 + NH3 + H2O = (Cu(NH3)4(H2O)2){+2} + NH4Cl + OH{-} =>
CuCl2 + 6 NH3 + 4 H2O = (Cu(NH3)4(H2O)2){+2} + 2 NH4Cl + 2 OH{-}
C2H2 + KMnO4 + H2O = C2H2O4 + MnO2 + KOH =>
3 C2H2 + 8 KMnO4 + 4 H2O = 3 C2H2O4 + 8 MnO2 + 8 KOH
CaO(aq) + HCl = CaCl2 + H2O =>
CaO(aq) + 2 HCl = CaCl2 + H2O
O2 + PbS = PbOSO2 =>
3 O2 + 2 PbS = 2 PbOSO2
NaOH(aq) + (NH4)2SO4(aq) = Na2SO4(s) + NH4OH(aq) =>
2 NaOH(aq) + (NH4)2SO4(aq) = Na2SO4(s) + 2 NH4OH(aq)
Cl2 + H3 = HCl2 =>
3 Cl2 + H3 = 3 HCl2
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 12/03/23
Equations balanced on 01/02/23
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