Equations balanced on the previous day | Equations balanced on the next day |
HClO4 + H2SO4 = O4ClSO3H + H2O
AlCl3(aq) + Pb(NO3)2(aq) = Al(NO3)3(aq) + PbCl2 =>
2 AlCl3(aq) + 3 Pb(NO3)2(aq) = 2 Al(NO3)3(aq) + 3 PbCl2
FeTiO3 + NH4F + O2 = (NH4)2TiF6 + H2O + NH3 + Fe2O3 =>
4 FeTiO3 + 24 NH4F + O2 = 4(NH4)2TiF6 + 8 H2O + 16 NH3 + 2 Fe2O3
Cl4 + H2O = HCl + HClO3 =>
3 Cl4 + 6 H2O = 10 HCl + 2 HClO3
SO3{2-} + MnO4{-} + H{+} = SO4{2-} + Mn{2+} + OH{-} =>
5 SO3{2-} + 2 MnO4{-} + 3 H{+} = 5 SO4{2-} + 2 Mn{2+} + 3 OH{-}
NH4Cl + Sm(OH)3 = NH4OH + SmCl3 =>
3 NH4Cl + Sm(OH)3 = 3 NH4OH + SmCl3
CH3CH2CH2COH + KMnO4 + H2SO4 = CH3CH2COOH + K2SO4 + MnSO4 + H2O =>
3 CH3CH2CH2COH + 2 KMnO4 + 3 H2SO4 = 4 CH3CH2COOH + K2SO4 + 2 MnSO4 + 3 H2O
MnSO4 + KMnO4 + H2O = MnO2 + K2SO4 + H2SO4 =>
3 MnSO4 + 2 KMnO4 + 2 H2O = 5 MnO2 + K2SO4 + 2 H2SO4
Ba(NO3)2 + K2CrO7 = BaCrO7 + K(NO3) =>
Ba(NO3)2 + K2CrO7 = BaCrO7 + 2 K(NO3)
NH4Cl + Sm(OH)3 = NH4OH + SmCl3 =>
3 NH4Cl + Sm(OH)3 = 3 NH4OH + SmCl3
FeCl2 + Na3PO4 = Fe3(PO4)2 + Na + Cl =>
3 FeCl2 + 2 Na3PO4 = Fe3(PO4)2 + 6 Na + 6 Cl
CH3CHO2CH3 + NO = CH3CHOCH3 + NO2 =>
CH3CHO2CH3 + NO = CH3CHOCH3 + NO2
Zn(C2H3O2)2 + Al2(SO4)3 = ZnSO4 + Al(C2H3O2)3 =>
3 Zn(C2H3O2)2 + Al2(SO4)3 = 3 ZnSO4 + 2 Al(C2H3O2)3
C6H5NO2 + Cl2 = C6H4NO2Cl + HCl =>
C6H5NO2 + Cl2 = C6H4NO2Cl + HCl
Cl2 + KOH = KClO3 + KCl + H2O =>
3 Cl2 + 6 KOH = KClO3 + 5 KCl + 3 H2O
C6H12 + O2 = O2H2 + C6 =>
C6H12 + 6 O2 = 6 O2H2 + C6
Na2SiO3 + CH3COOH = CH3COONa + H2SiO3 =>
Na2SiO3 + 2 CH3COOH = 2 CH3COONa + H2SiO3
AlBr3(s) = Al(aq) + Br(aq) =>
AlBr3(s) = Al(aq) + 3 Br(aq)
C2H6 + Br2 = CBr2 + HBr =>
C2H6 + 5 Br2 = 2 CBr2 + 6 HBr
H2SO4 + BaO2 = H2O2 + BaSO4 =>
H2SO4 + BaO2 = H2O2 + BaSO4
C9H12 + KMnO4 + H2SO4 = C7H6O2 + K2SO4 + MnSO4 + H2O =>
35 C9H12 + 66 KMnO4 + 99 H2SO4 = 45 C7H6O2 + 33 K2SO4 + 66 MnSO4 + 174 H2O
He + S = HeS =>
He + S = HeS
CaCl2 + HNO3 = Ca(NO3)2 + HCl =>
CaCl2 + 2 HNO3 = Ca(NO3)2 + 2 HCl
CaCl2 + HNO3 = Ca(NO3)2 + HCl =>
CaCl2 + 2 HNO3 = Ca(NO3)2 + 2 HCl
HCl + NaHSO3 = NaCl + SO2 + H2O =>
HCl + NaHSO3 = NaCl + SO2 + H2O
BaCO3 = BaO + CO2 =>
BaCO3 = BaO + CO2
CaCl2 + HNO3 = Ca(NO3)2 + HCl =>
CaCl2 + 2 HNO3 = Ca(NO3)2 + 2 HCl
Ag(NH3)2 + COO = AgO + NH3 + CO =>
Ag(NH3)2 + COO = AgO + 2 NH3 + CO
CaC2(s) + H2O(l) = C2H2(g) + Ca(OH)2(aq) =>
CaC2(s) + 2 H2O(l) = C2H2(g) + Ca(OH)2(aq)
NaHCO3 = Na2C2O2 + H2O + O2 =>
4 NaHCO3 = 2 Na2C2O2 + 2 H2O + 3 O2
NH4Cl + Sm(OH)3 = NH4OH + SmCl3 =>
3 NH4Cl + Sm(OH)3 = 3 NH4OH + SmCl3
C12H22O11 + Cu(OH)2 = C12H22O12 + Cu2O + H2O =>
C12H22O11 + 2 Cu(OH)2 = C12H22O12 + Cu2O + 2 H2O
C4H9Br + Br2 = C4H8Br2 + HBr =>
C4H9Br + Br2 = C4H8Br2 + HBr
K3PO4 + ZnSO4 = K2SO4 + Zn3(PO4)2 =>
2 K3PO4 + 3 ZnSO4 = 3 K2SO4 + Zn3(PO4)2
C + O2 = CO2 =>
C + O2 = CO2
Ba(NO3)2 = Ba + NO3 =>
Ba(NO3)2 = Ba + 2 NO3
K3N + HOH = K3OH + NH =>
K3N + HOH = K3OH + NH
H2SO3(aq) + NH3(aq) = NH4 + HSO3 =>
H2SO3(aq) + NH3(aq) = NH4 + HSO3
Fe2O3 + C(s) = Fe(s) + CO2 =>
2 Fe2O3 + 3 C(s) = 4 Fe(s) + 3 CO2
H2O(l) + (CN)2(g) = H2C2O4(aq) + NH3(g) =>
4 H2O(l) + (CN)2(g) = H2C2O4(aq) + 2 NH3(g)
CF4 + Br2 = CBr4 + F2 =>
CF4 + 2 Br2 = CBr4 + 2 F2
Al2(SO4)3 = Al3 + SO4 =>
3 Al2(SO4)3 = 2 Al3 + 9 SO4
NH4Cl + Sm(OH)3 = NH3 + H2O + SmCl3 =>
3 NH4Cl + Sm(OH)3 = 3 NH3 + 3 H2O + SmCl3
La4[Fe(CN)6]3 + La2(Cr5O16)3 + H2SO4 = La2(SO3)3 + Fe2(S2O7)3 + Cr(SO4)3 + La(NO3)3 + C10H8 + H2O =>
10 La4[Fe(CN)6]3 + 171 La2(Cr5O16)3 + 8268 H2SO4 = 161 La2(SO3)3 + 15 Fe2(S2O7)3 + 2565 Cr(SO4)3 + 60 La(NO3)3 + 18 C10H8 + 8196 H2O
NaCl + KMnO4 + H2SO4 = NaSO4 + MnSO4 + K2SO4 + H2O + Cl2 =>
10 NaCl + 4 KMnO4 + 16 H2SO4 = 10 NaSO4 + 4 MnSO4 + 2 K2SO4 + 16 H2O + 5 Cl2
KI + H2SO4 = H2O + I2 + K2SO4 + H2S =>
8 KI + 5 H2SO4 = 4 H2O + 4 I2 + 4 K2SO4 + H2S
HNO2 + KOH = KNO2 + HOH =>
HNO2 + KOH = KNO2 + HOH
NH3 + BrO = N2 + Br + H2O =>
2 NH3 + 3 BrO = N2 + 3 Br + 3 H2O
HCN(aq) + Ca(OH)2(aq) = Ca(CN)2(aq) + H2O(l) =>
2 HCN(aq) + Ca(OH)2(aq) = Ca(CN)2(aq) + 2 H2O(l)
Al + O2 = Al2O3 =>
4 Al + 3 O2 = 2 Al2O3
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 12/05/23
Equations balanced on 01/04/23
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