Equations balanced on the previous day | Equations balanced on the next day |
Zn + Ni(NO3)2 = Zn(NO3)2 + Ni
Fe(s) + S8(s) = FeS(s) =>
8 Fe(s) + S8(s) = 8 FeS(s)
Na3PO4 + CaCl2 = NaCl + Ca3(PO4)2 =>
2 Na3PO4 + 3 CaCl2 = 6 NaCl + Ca3(PO4)2
C22H45COOH + O2 = CO2 + H2O =>
2 C22H45COOH + 67 O2 = 46 CO2 + 46 H2O
Ba(s) + H2SO4(aq) = BaSO4(aq) + SO2(g) + H2O(l) =>
Ba(s) + 2 H2SO4(aq) = BaSO4(aq) + SO2(g) + 2 H2O(l)
FrBr = Fr + Br2 =>
2 FrBr = 2 Fr + Br2
Fe + Cl2 = FeCl3 =>
2 Fe + 3 Cl2 = 2 FeCl3
Fe(NH4)2(SO4)2*6H2O + H2C2O4 = FeC2O4 + H2SO4 + (NH4)2SO4 + H2O =>
Fe(NH4)2(SO4)2*6H2O + H2C2O4 = FeC2O4 + H2SO4 + (NH4)2SO4 + 6 H2O
CaCl2 + Na3PO4 = Ca3(PO4)2 + NaCl =>
3 CaCl2 + 2 Na3PO4 = Ca3(PO4)2 + 6 NaCl
CS2 + NH3 = H2S + NH4SCN =>
CS2 + 2 NH3 = H2S + NH4SCN
K2Cr2O7 + KI + HCl = CrCl3 + I2 + KCl + H2O =>
K2Cr2O7 + 6 KI + 14 HCl = 2 CrCl3 + 3 I2 + 8 KCl + 7 H2O
NaOH + Sn(C2H3O2)4 = C2H3NaO2 + Sn(OH)4 =>
4 NaOH + Sn(C2H3O2)4 = 4 C2H3NaO2 + Sn(OH)4
Ca[Ag(CN)]2 + HCl = Ag(CN) + CaCl2 + H2 =>
Ca[Ag(CN)]2 + 2 HCl = 2 Ag(CN) + CaCl2 + H2
CaCl2(aq) + Na3(PO4)(aq) = NaCl + Ca3(PO4)2 =>
3 CaCl2(aq) + 2 Na3(PO4)(aq) = 6 NaCl + Ca3(PO4)2
Ba(s) + H2SO4(aq) = BaSO4(aq) + SO2(g) + H2O(l) =>
Ba(s) + 2 H2SO4(aq) = BaSO4(aq) + SO2(g) + 2 H2O(l)
NaOH + Sn(C2H3O2)4 = C2H3NaO2 + Sn(OH)4 =>
4 NaOH + Sn(C2H3O2)4 = 4 C2H3NaO2 + Sn(OH)4
Ba(s) + H2SO4(aq) = BaSO4(aq) + SO2(g) + H2O(l) =>
Ba(s) + 2 H2SO4(aq) = BaSO4(aq) + SO2(g) + 2 H2O(l)
KHCO3 = K2CO3 + H2O + CO2 =>
2 KHCO3 = K2CO3 + H2O + CO2
Ag + Cu(NO3)2 = Cu + AgNO3 =>
2 Ag + Cu(NO3)2 = Cu + 2 AgNO3
NaCl + NH4NO3 = NaNO3 + NH4Cl =>
NaCl + NH4NO3 = NaNO3 + NH4Cl
NaOH + Sn(C2H3O2)4 = C2H3NaO2 + Sn(OH)4 =>
4 NaOH + Sn(C2H3O2)4 = 4 C2H3NaO2 + Sn(OH)4
Ag2O = Ag + O2 =>
2 Ag2O = 4 Ag + O2
KClO3 = KCl + O2 =>
2 KClO3 = 2 KCl + 3 O2
NaOH + Sn(C2H3O2)4 = C2H3NaO2 + Sn(OH)4 =>
4 NaOH + Sn(C2H3O2)4 = 4 C2H3NaO2 + Sn(OH)4
NaOH + Sn(C2H3O2)4 = C2H3NaO2 + Sn(OH)4 =>
4 NaOH + Sn(C2H3O2)4 = 4 C2H3NaO2 + Sn(OH)4
NaCl + NH4NO3 = NaNO3 + NH4Cl =>
NaCl + NH4NO3 = NaNO3 + NH4Cl
H2 + C6H10 = C6H12 =>
H2 + C6H10 = C6H12
LiC = C6 + Li =>
6 LiC = C6 + 6 Li
Fe + Cl2 = FeCl3 =>
2 Fe + 3 Cl2 = 2 FeCl3
NaClO3 = NaCl + O2 =>
2 NaClO3 = 2 NaCl + 3 O2
C2H6 + O2 = CO2 + H2O =>
2 C2H6 + 7 O2 = 4 CO2 + 6 H2O
NaOH + Sn(C2H3O2)4 = C2H3NaO2 + Sn(OH)4 =>
4 NaOH + Sn(C2H3O2)4 = 4 C2H3NaO2 + Sn(OH)4
(NH4)2Fe(SO4)2 = FeSO4 + NH3 + H2O + SO2 + O2 =>
2(NH4)2Fe(SO4)2 = 2 FeSO4 + 4 NH3 + 2 H2O + 2 SO2 + O2
Ba(s) + H2SO4(aq) = BaSO4(aq) + SO2(g) + H2O =>
Ba(s) + 2 H2SO4(aq) = BaSO4(aq) + SO2(g) + 2 H2O
NaOH + H2(SO4)2 = NaSO4 + H2O =>
2 NaOH + H2(SO4)2 = 2 NaSO4 + 2 H2O
C8H16 + O2 = CO2 + H2O =>
C8H16 + 12 O2 = 8 CO2 + 8 H2O
C3H8 + O2 = CO2 + H2O =>
C3H8 + 5 O2 = 3 CO2 + 4 H2O
FeSO4 + Na3[Fe(CN)6] = Fe3[Fe(CN)6]2 + Na2SO4 =>
3 FeSO4 + 2 Na3[Fe(CN)6] = Fe3[Fe(CN)6]2 + 3 Na2SO4
Ba(s) + H2SO4(aq) = BaSO4(aq) + SO2(g) + H2O(l) =>
Ba(s) + 2 H2SO4(aq) = BaSO4(aq) + SO2(g) + 2 H2O(l)
H3PO4 + SnCl2 = HCl + Sn3(PO4)2 =>
2 H3PO4 + 3 SnCl2 = 6 HCl + Sn3(PO4)2
Ba(s) + H2SO4(aq) = BaSO4(aq) + SO2(g) + H2O(l) =>
Ba(s) + 2 H2SO4(aq) = BaSO4(aq) + SO2(g) + 2 H2O(l)
C4N2H6 + BrC4H9 = C8N2H15 + Br =>
C4N2H6 + BrC4H9 = C8N2H15 + Br
MgBr + O2 = Br2 + Mg2O2 =>
2 MgBr + O2 = Br2 + Mg2O2
Ag(CH3COOH) + CaCl2 = AgCl + Ca(CH3COOH)2 =>
2 Ag(CH3COOH) + CaCl2 = 2 AgCl + Ca(CH3COOH)2
Sr(No3)2 + Fe(No3)39H2O + NaOH = SrFe12O19 + NaNo3 + H2O + O =>
Sr(No3)2 + 12 Fe(No3)39H2O + 470 NaOH = SrFe12O19 + 470 NaNo3 + 247 H2O + 216 O
NaOH + Sn(C2H3O2)4 = C2H3NaO2 + Sn(OH)4 =>
4 NaOH + Sn(C2H3O2)4 = 4 C2H3NaO2 + Sn(OH)4
Ba(s) + H2SO4(aq) = BaSO4(s) + H2(g) =>
Ba(s) + H2SO4(aq) = BaSO4(s) + H2(g)
Zn(s) + AgNO3(aq) = Zn(NO3) + Ag(s) =>
Zn(s) + AgNO3(aq) = Zn(NO3) + Ag(s)
KMnO4 + FeCl2 + H2SO4 = MnSO4 + Fe2(SO4)2 + Cl2 + K2SO4 + H2O =>
4 KMnO4 + 10 FeCl2 + 16 H2SO4 = 4 MnSO4 + 5 Fe2(SO4)2 + 10 Cl2 + 2 K2SO4 + 16 H2O
NaOH + Sn(C2H3O2)4 = C2H3NaO2 + Sn(OH)4 =>
4 NaOH + Sn(C2H3O2)4 = 4 C2H3NaO2 + Sn(OH)4
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 12/30/23
Equations balanced on 01/29/23
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