Equations balanced on the previous day | Equations balanced on the next day |
C4H10O + H2CrO4 + H2SO4 = C4H8O2 + CrSO4 + 3 H2O
Na2CO3 = Na2O + CO2 =>
Na2CO3 = Na2O + CO2
CrI3 + KOH + Br2 = K2CrO4 + KIO3 + KBr + H2O =>
2 CrI3 + 52 KOH + 21 Br2 = 2 K2CrO4 + 6 KIO3 + 42 KBr + 26 H2O
H2SO4 + NaOH = Na2SO4 + H2O =>
H2SO4 + 2 NaOH = Na2SO4 + 2 H2O
CH3CH2OH + Cr2O7{-2} + H{+} = CH3CHO + Cr{+3} + H2O =>
3 CH3CH2OH + Cr2O7{-2} + 8 H{+} = 3 CH3CHO + 2 Cr{+3} + 7 H2O
CrI + KOH + Br2 = KIO3 + K2CrO4 + KBr + H2O =>
2 CrI + 28 KOH + 11 Br2 = 2 KIO3 + 2 K2CrO4 + 22 KBr + 14 H2O
NH3 + Cu(NO3)2 = CuH3 + N(NO3)2 =>
NH3 + Cu(NO3)2 = CuH3 + N(NO3)2
Fe + Cl2 = FeCl3 =>
2 Fe + 3 Cl2 = 2 FeCl3
CH3OH + CH3CH2CH2CH2OH = CH3CH2CH2H2O2CH2CH3 =>
CH3OH + CH3CH2CH2CH2OH = CH3CH2CH2H2O2CH2CH3
AgNO3(aq) + Ca(OH)2(aq) = Ca(NO3)2(aq) + AgOH(aq) =>
2 AgNO3(aq) + Ca(OH)2(aq) = Ca(NO3)2(aq) + 2 AgOH(aq)
CrI + KOH + Br2 = KIO3 + K2CrO4 + KBr + H2O =>
2 CrI + 28 KOH + 11 Br2 = 2 KIO3 + 2 K2CrO4 + 22 KBr + 14 H2O
CrI + KOH + Br2 = KIO3 + K2CrO4 + KBr + H2O =>
2 CrI + 28 KOH + 11 Br2 = 2 KIO3 + 2 K2CrO4 + 22 KBr + 14 H2O
FeOH + HNO2 = FeNO2 + HOH =>
FeOH + HNO2 = FeNO2 + HOH
C3H8 = C3H4 + H2 =>
C3H8 = C3H4 + 2 H2
AgNO3 + KCl = AgCl + KNO3 =>
AgNO3 + KCl = AgCl + KNO3
FeOH + HNO2 = FeNO2 + HOH =>
FeOH + HNO2 = FeNO2 + HOH
BaO2 + Cr2(SO4)3 + KOH = K2CrO4 + BaSO4 + H2O =>
3 BaO2 + Cr2(SO4)3 + 4 KOH = 2 K2CrO4 + 3 BaSO4 + 2 H2O
HNO3 + Ba(OH)2 = Ba(NO3)2 + H2O =>
2 HNO3 + Ba(OH)2 = Ba(NO3)2 + 2 H2O
CuOH2O = CuO + H2O =>
CuOH2O = CuO + H2O
Sn + Mn(NO3)2 = Sn(NO3)4 + Mn =>
Sn + 2 Mn(NO3)2 = Sn(NO3)4 + 2 Mn
N + O = N10O5 =>
10 N + 5 O = N10O5
CaCl2 + Na2Cr2O7 + H3AsO4 = Cr2(AsO4)2 + Ca3(AsO4)2 + Na2AsO4 + Cl2 + H2O =>
15 CaCl2 + 6 Na2Cr2O7 + 28 H3AsO4 = 6 Cr2(AsO4)2 + 5 Ca3(AsO4)2 + 6 Na2AsO4 + 15 Cl2 + 42 H2O
FeS2 + HNO3 + HCl = FeCl3 + H2O + H2SO4 + NO =>
FeS2 + 5 HNO3 + 3 HCl = FeCl3 + 2 H2O + 2 H2SO4 + 5 NO
NaHCO3 = Na2CO3 + CO2 + H2O =>
2 NaHCO3 = Na2CO3 + CO2 + H2O
FeCl3 + (NH4)2CrO4 = Fe2(CrO4)3 + NH4Cl =>
2 FeCl3 + 3(NH4)2CrO4 = Fe2(CrO4)3 + 6 NH4Cl
HNO3 + Ba(OH)2 = Ba(NO3)2 + H2O =>
2 HNO3 + Ba(OH)2 = Ba(NO3)2 + 2 H2O
Al(NO3)3 + Pb(OH)2 = Al(OH)3 + Pb(NO3)2 =>
2 Al(NO3)3 + 3 Pb(OH)2 = 2 Al(OH)3 + 3 Pb(NO3)2
CrI + KOH + Br2 = KIO3 + K2CrO4 + KBr + H2O =>
2 CrI + 28 KOH + 11 Br2 = 2 KIO3 + 2 K2CrO4 + 22 KBr + 14 H2O
Ba(CH3CO2)2 + (NH4)2SO4 = BaSO4 + CH3CO2 + NH4 =>
Ba(CH3CO2)2 + (NH4)2SO4 = BaSO4 + 2 CH3CO2 + 2 NH4
Hg2 + CO3 = Hg2(CO3)2 =>
Hg2 + 2 CO3 = Hg2(CO3)2
CoCl2 + Li2CO3 = CoCO3 + LiCl =>
CoCl2 + Li2CO3 = CoCO3 + 2 LiCl
C6H5CHCH2 + KMnO4 + H2O = C6H5CH(OH)CH2(OH) + KOH + MnO2 =>
3 C6H5CHCH2 + 2 KMnO4 + 4 H2O = 3 C6H5CH(OH)CH2(OH) + 2 KOH + 2 MnO2
CoCl2 + Li2CO3 = CoCO3 + LiCl =>
CoCl2 + Li2CO3 = CoCO3 + 2 LiCl
C8H13O7 + O2 = CO2 + H2O =>
4 C8H13O7 + 31 O2 = 32 CO2 + 26 H2O
PH4 = P2 + H2 =>
2 PH4 = P2 + 4 H2
NaHCO3 = Na2CO3 + CO2 + H2O =>
2 NaHCO3 = Na2CO3 + CO2 + H2O
Pb(NO3)2 + NH4Br = PbBr2 + NH4NO3 =>
Pb(NO3)2 + 2 NH4Br = PbBr2 + 2 NH4NO3
CrI + KOH + Br2 = KIO3 + K2CrO4 + KBr + H2O =>
2 CrI + 28 KOH + 11 Br2 = 2 KIO3 + 2 K2CrO4 + 22 KBr + 14 H2O
CH2CH2 + KMnO4 + H2O = CH2OHCH2OH + MnO2 + KOH =>
3 CH2CH2 + 2 KMnO4 + 4 H2O = 3 CH2OHCH2OH + 2 MnO2 + 2 KOH
As2O3 + I2 + H2O = HAs2O5 + HI =>
2 As2O3 + 3 I2 + 4 H2O = 2 HAs2O5 + 6 HI
HCl(aq) + Mg(OH)2(aq) = MgCl2(aq) + H2O(l) =>
2 HCl(aq) + Mg(OH)2(aq) = MgCl2(aq) + 2 H2O(l)
CrI + KOH + Br2 = KIO3 + K2CrO4 + KBr + H2O =>
2 CrI + 28 KOH + 11 Br2 = 2 KIO3 + 2 K2CrO4 + 22 KBr + 14 H2O
PH4 = P2 + H2 =>
2 PH4 = P2 + 4 H2
Hg2 + CO3 = Hg2(CO3)2 =>
Hg2 + 2 CO3 = Hg2(CO3)2
CrI + KOH + Br2 = KIO3 + K2CrO4 + KBr + H2O =>
2 CrI + 28 KOH + 11 Br2 = 2 KIO3 + 2 K2CrO4 + 22 KBr + 14 H2O
FeOH + HNO2 = FeNO2 + HOH =>
FeOH + HNO2 = FeNO2 + HOH
N + O = N10O5 =>
10 N + 5 O = N10O5
Ca2 + Br2 = CaBr2 =>
Ca2 + 2 Br2 = 2 CaBr2
N + O = N10O5 =>
10 N + 5 O = N10O5
N + O = N10O5 =>
10 N + 5 O = N10O5
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 01/03/24
Equations balanced on 02/02/23
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