Equations balanced on the previous day | Equations balanced on the next day |
2 H2O + 4 Fe(OH)2 + MnO4 = MnO2 + 4 Fe(OH)3
C8H18 + OH = CO2 + H2O =>
C8H18 + 50 OH = 8 CO2 + 34 H2O
BaO + SiO2 = BaSiO3 =>
BaO + SiO2 = BaSiO3
Al(SO4)3 + NaOH = Al(OH)3 + Na + SO4 =>
Al(SO4)3 + 3 NaOH = Al(OH)3 + 3 Na + 3 SO4
Cu + O2 = Cu2O =>
4 Cu + O2 = 2 Cu2O
HNO3 + Sn2 = Sn(NO3)2 + H2 =>
4 HNO3 + Sn2 = 2 Sn(NO3)2 + 2 H2
Ba + HCl = BaHCl =>
Ba + HCl = BaHCl
SO2(q) + O2(g) = SO3(g) =>
2 SO2(q) + O2(g) = 2 SO3(g)
(NH4)2SO4 + BCl2 = (NH4)Cl + BSO4 =>
(NH4)2SO4 + BCl2 = 2(NH4)Cl + BSO4
K2S + HNO3 = K2SO4 + NO + H2O =>
3 K2S + 8 HNO3 = 3 K2SO4 + 8 NO + 4 H2O
C5H10 + O2 = H2O + CO5 =>
C5H10 + 15 O2 = 5 H2O + 5 CO5
O2N + H2N = O3NH + NO =>
5 O2N + H2N = 2 O3NH + 4 NO
Ce(NO3)3*6H2O + ZrOCl2*8H2O + Al(NO3)3*9H2O + C6H8O7*H2O = CeZrAl + N2 + CO2 + H2O + Cl2 =>
9 Ce(NO3)3*6H2O + 9 ZrOCl2*8H2O + 9 Al(NO3)3*9H2O + 19 C6H8O7*H2O = 9 CeZrAl + 27 N2 + 114 CO2 + 302 H2O + 9 Cl2
NaBiO3 + MnSO4 + H2SO4 = NaSO4 + HMnO4 + Bi2(SO4)3 + H2O =>
10 NaBiO3 + 2 MnSO4 + 23 H2SO4 = 10 NaSO4 + 2 HMnO4 + 5 Bi2(SO4)3 + 22 H2O
Ba2 + O2 = BaO2 =>
Ba2 + 2 O2 = 2 BaO2
HBr(aq) + Ba(OH)2(aq) = H2O(l) + BaBr2(aq) =>
2 HBr(aq) + Ba(OH)2(aq) = 2 H2O(l) + BaBr2(aq)
Co(NO3)2 + CoCl2 = CoCo + Cl2(NO3)2 =>
Co(NO3)2 + CoCl2 = CoCo + Cl2(NO3)2
H2SO4 + As2O3 + H2O = H3AsO4 + SO2 =>
2 H2SO4 + As2O3 + H2O = 2 H3AsO4 + 2 SO2
C3H6 + NH3 + O2 = C3H3N + H2O =>
2 C3H6 + 2 NH3 + 3 O2 = 2 C3H3N + 6 H2O
HCl + Na(OH)2 = H(OH) + NaCl2 =>
2 HCl + Na(OH)2 = 2 H(OH) + NaCl2
Zn + HClO4 = ZnHClO4 =>
Zn + HClO4 = ZnHClO4
(Cr2O7)2{-} + C2H5OH + H{+} = Cr3{+} + CH3COOH + H2O =>
12(Cr2O7)2{-} + 77 C2H5OH + 28 H{+} = 16 Cr3{+} + 77 CH3COOH + 91 H2O
HCOOCH2CH2CH3 + NaHCO3 = NaCOOCH2CH2CH3 + H2O + CO2 =>
HCOOCH2CH2CH3 + NaHCO3 = NaCOOCH2CH2CH3 + H2O + CO2
Al + NaOH + Cl2 = NaAlO2 + NaCl + H2O =>
2 Al + 8 NaOH + 3 Cl2 = 2 NaAlO2 + 6 NaCl + 4 H2O
KMnO4 + HCl = KCl + MnCl2 + H2O + Cl2 =>
2 KMnO4 + 16 HCl = 2 KCl + 2 MnCl2 + 8 H2O + 5 Cl2
KI + SO4 = I + KSO4 =>
KI + SO4 = I + KSO4
(Cr2O7)2{-} + C2H5OH + H{+} = Cr3{+} + CH3COOH + H2O =>
12(Cr2O7)2{-} + 77 C2H5OH + 28 H{+} = 16 Cr3{+} + 77 CH3COOH + 91 H2O
HCl + Na(OH)2 = H(OH) + NaCl2 =>
2 HCl + Na(OH)2 = 2 H(OH) + NaCl2
HCl + Na(OH)2 = H(OH) + NaCl2 =>
2 HCl + Na(OH)2 = 2 H(OH) + NaCl2
Na2CO3 + CH3OOH = CH3OONa + H2O + CO2 =>
Na2CO3 + 2 CH3OOH = 2 CH3OONa + H2O + CO2
CoCl2 + HCl = CoCl4 + H =>
CoCl2 + 2 HCl = CoCl4 + 2 H
(NH4)2SO4 + BCl2 = (NH4)Cl + BSO4 =>
(NH4)2SO4 + BCl2 = 2(NH4)Cl + BSO4
C96H141O66 + O2 = CO2 + H2O =>
4 C96H141O66 + 393 O2 = 384 CO2 + 282 H2O
NaAl2 + H2O2 = Na2O2 + Al + H =>
2 NaAl2 + H2O2 = Na2O2 + 4 Al + 2 H
C6H5COOCH3 + O2 = H2O + CO2 =>
C6H5COOCH3 + 9 O2 = 4 H2O + 8 CO2
KOH + H3PO4 = K3PO4 + H2O =>
3 KOH + H3PO4 = K3PO4 + 3 H2O
Al2(SO4)3 + H2 = Al2O3 + SO2 + H2O =>
Al2(SO4)3 + 3 H2 = Al2O3 + 3 SO2 + 3 H2O
(Cr2O7)2{-} + C2H5OH + H{+} = Cr3{+} + CH3COOH + H2O =>
12(Cr2O7)2{-} + 77 C2H5OH + 28 H{+} = 16 Cr3{+} + 77 CH3COOH + 91 H2O
(Cr2O7)2{-} + C2H5OH + H{+} = Cr3{+} + CH3COOH + H2O =>
12(Cr2O7)2{-} + 77 C2H5OH + 28 H{+} = 16 Cr3{+} + 77 CH3COOH + 91 H2O
HCl + Na(OH)2 = H(OH) + NaCl2 =>
2 HCl + Na(OH)2 = 2 H(OH) + NaCl2
KCl + AgNO3 = Ag + KClNO3 =>
KCl + AgNO3 = Ag + KClNO3
CH3COOH + Na2CO3 = CH3COONa2 + CO2 + H2O =>
9 CH3COOH + 8 Na2CO3 = 8 CH3COONa2 + 10 CO2 + 6 H2O
HCl + Na(OH)2 = H(OH) + NaCl2 =>
2 HCl + Na(OH)2 = 2 H(OH) + NaCl2
C2H5OH(g) + H2O = H2(g) + CO2(g) =>
C2H5OH(g) + 3 H2O = 6 H2(g) + 2 CO2(g)
IO3{-} + H3O{+} + SO3{2-} = I + SO4{2-} + H2 = =>
2 IO3{-} + 2 H3O{+} + 8 SO3{2-} = 2 I + 8 SO4{2-} + 3 H2
C7H8(s) + O2(g) = H2O + C =>
C7H8(s) + 2 O2(g) = 4 H2O + 7 C
HCl + Na(OH)2 = H(OH) + NaCl2 =>
2 HCl + Na(OH)2 = 2 H(OH) + NaCl2
H2O + CO2 + CaCO3 = Ca + HCO3 =>
H2O + CO2 + CaCO3 = Ca + 2 HCO3
NH2CONH2 + H2O = NH4COONH2 =>
NH2CONH2 + H2O = NH4COONH2
B(C2H5O)3 + O2 = B(OH)3 + CO2 + H2O =>
B(C2H5O)3 + 9 O2 = B(OH)3 + 6 CO2 + 6 H2O
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 01/07/24
Equations balanced on 02/06/23
Оставьте нам отзыв о своем опыте работы с химической балансировкой уравнений.