Equations balanced on the previous day | Equations balanced on the next day |
2 Cr(NO3)3 + 3 H2O2 + 10 NaOH = 2 Na2CrO4 + 6 NaNO3 + 8 H2O
KMnO2 + HCl = MnCl2 + H2O + Cl2 + KCl =>
2 KMnO2 + 8 HCl = 2 MnCl2 + 4 H2O + Cl2 + 2 KCl
Ag + CuSO4(aq) = Ag2SO4 + Cu =>
2 Ag + CuSO4(aq) = Ag2SO4 + Cu
CdCl2 + Na2CO4 = CdCO4 + NaCl =>
CdCl2 + Na2CO4 = CdCO4 + 2 NaCl
KNO3 + NH4Cl = KCl + N2O + H2O =>
KNO3 + NH4Cl = KCl + N2O + 2 H2O
C6H12O + K2Cr2O7 + H2SO4 = C6H10O + Cr2(SO4)3 + K2SO4 + H2O =>
3 C6H12O + K2Cr2O7 + 4 H2SO4 = 3 C6H10O + Cr2(SO4)3 + K2SO4 + 7 H2O
KI + Br2 + KOH = KIO3 + KBr + H2O =>
KI + 3 Br2 + 6 KOH = KIO3 + 6 KBr + 3 H2O
Al + KNO3 + KOH + HOH = NH3 + KAl(OH)4 =>
8 Al + 3 KNO3 + 5 KOH + 18 HOH = 3 NH3 + 8 KAl(OH)4
Fe + H2SnCl6 = Fe2(SnCl6)3 + H2 =>
2 Fe + 3 H2SnCl6 = Fe2(SnCl6)3 + 3 H2
CaCO3 + CH3COOH = CaCH2 + H2O + CO2 =>
CaCO3 + CH3COOH = CaCH2 + H2O + 2 CO2
Fe2O3(H2O) + Sc(OH)3 = ScO2(OH)2 + H2O + Fe =>
Fe2O3(H2O) + 2 Sc(OH)3 = 2 ScO2(OH)2 + 2 H2O + 2 Fe
Pb(ClO4)2 + NaOH = Na(ClO4) + Pb(OH)2 =>
Pb(ClO4)2 + 2 NaOH = 2 Na(ClO4) + Pb(OH)2
CdCl2 + Na2CO4 = CdCO4 + NaCl =>
CdCl2 + Na2CO4 = CdCO4 + 2 NaCl
CuCl2 + Pb = PbCl + Cu =>
CuCl2 + 2 Pb = 2 PbCl + Cu
NO3 + Zn + H2O = Zn(OH)4 + NH3 =>
4 NO3 + 9 Zn + 24 H2O = 9 Zn(OH)4 + 4 NH3
PbO2 + NaCrOH4 + NaOH = NaCrO4 + Na2PbO2 + H2O =>
5 PbO2 + NaCrOH4 + 10 NaOH = NaCrO4 + 5 Na2PbO2 + 7 H2O
(Ca)25 + (H2O)25 = Ca(OH)2 + H2 =>
(Ca)25 + 2(H2O)25 = 25 Ca(OH)2 + 25 H2
Ca + Cl2(aq) = CaCl2(aq) =>
Ca + Cl2(aq) = CaCl2(aq)
CaCO3 + CH3COOH = CaCH2 + H2O + CO2 =>
CaCO3 + CH3COOH = CaCH2 + H2O + 2 CO2
As + NO3{-} + H2O = H3AsO3 + NO + OH{-} =>
As + NO3{-} + 2 H2O = H3AsO3 + NO + OH{-}
H2C204 + HNO2 = CO2 + NO + H2O =>
H2C204 + 818 HNO2 = 204 CO2 + 818 NO + 410 H2O
CaCO3 + CH3COOH = CaCH2 + H2O + CO2 =>
CaCO3 + CH3COOH = CaCH2 + H2O + 2 CO2
Ca(OH)2 + Cl2 = CaCl2 + Ca(ClO4)2 + H2O =>
8 Ca(OH)2 + 8 Cl2 = 7 CaCl2 + Ca(ClO4)2 + 8 H2O
K3PO4(aq) + ZnSO4(aq) = K2SO4 + Zn3(PO4)2 =>
2 K3PO4(aq) + 3 ZnSO4(aq) = 3 K2SO4 + Zn3(PO4)2
Ba3(PO4)2 + (NH4)2CO3 = BaCO3 + (NH4)3PO4 =>
Ba3(PO4)2 + 3(NH4)2CO3 = 3 BaCO3 + 2(NH4)3PO4
K2CrO7 + FeSO4 + H2SO4 = K2CrO4 + Fe2(SO4)3 + H2O =>
K2CrO7 + 6 FeSO4 + 3 H2SO4 = K2CrO4 + 3 Fe2(SO4)3 + 3 H2O
CuCl + C2H4(NH2)2 = Cu[C2H4(NH2)2] + Cl2 =>
2 CuCl + 2 C2H4(NH2)2 = 2 Cu[C2H4(NH2)2] + Cl2
CO2 + H3O = CO + H2O =>
CO2 + 2 H3O = CO + 3 H2O
Al + Si4 = Al4Si3 =>
16 Al + 3 Si4 = 4 Al4Si3
O3 + PbS = PbSO =>
O3 + 3 PbS = 3 PbSO
Cu(No3)2 + BaS = CuS + Ba(No3)2 =>
Cu(No3)2 + BaS = CuS + Ba(No3)2
Cu2S2 + HNO3 = CuSO4 + NO2 + H2O =>
Cu2S2 + 16 HNO3 = 2 CuSO4 + 16 NO2 + 8 H2O
Al + Si4 = Al4Si3 =>
16 Al + 3 Si4 = 4 Al4Si3
chlorine + sodiumhydroxide = sodiumchloride + sodiumchlorate + water =>
3 Cl2 + 6 NaOH = 5 NaCl + NaClO3 + 3 H2O
Co(OH)2 + HF = CoF2 + H2O =>
Co(OH)2 + 2 HF = CoF2 + 2 H2O
Cu2O + C3H8O3 = C + Cu + H2O =>
Cu2O + C3H8O3 = 3 C + 2 Cu + 4 H2O
Ba(OH)2 + H2O = OH{-} + BaO2H3{+} =>
Ba(OH)2 + H2O = OH{-} + BaO2H3{+}
Mn(CO)5 + O2 = MnO2 + CO2 =>
2 Mn(CO)5 + 7 O2 = 2 MnO2 + 10 CO2
KCIO3 + C = KCI + CO2 =>
2 KCIO3 + 3 C = 2 KCI + 3 CO2
FeSO4 + KMnO4 + H2SO4 = Fe2(SO4)3 + MnSO4 + H2O + K2SO4 =>
10 FeSO4 + 2 KMnO4 + 8 H2SO4 = 5 Fe2(SO4)3 + 2 MnSO4 + 8 H2O + K2SO4
H2NCH2COOH + Fe = H2NCH2COOFe + H2 =>
2 H2NCH2COOH + 2 Fe = 2 H2NCH2COOFe + H2
KClO3 + CH2O = KCl + CO2 + H2O =>
2 KClO3 + 3 CH2O = 2 KCl + 3 CO2 + 3 H2O
KCN + H2SO4 + Na = Na2SO4 + HCN + K =>
2 KCN + H2SO4 + 2 Na = Na2SO4 + 2 HCN + 2 K
Al + Si4 = Al4Si3 =>
16 Al + 3 Si4 = 4 Al4Si3
HBr(aq) + KF(aq) = HF + KBr =>
HBr(aq) + KF(aq) = HF + KBr
Au + KCN + O2 + H2O = KAu(CN)2 + KOH =>
4 Au + 8 KCN + O2 + 2 H2O = 4 KAu(CN)2 + 4 KOH
CdCl2 + Na2CO4 = CdCO4 + NaCl =>
CdCl2 + Na2CO4 = CdCO4 + 2 NaCl
Fe + CrO3 + HCl = FeCl2 + CrCl3 + H2O =>
3 Fe + 2 CrO3 + 12 HCl = 3 FeCl2 + 2 CrCl3 + 6 H2O
CuCl + C2H4(NH2)2 = Cu[C2H4(NH2)2] + Cl2 =>
2 CuCl + 2 C2H4(NH2)2 = 2 Cu[C2H4(NH2)2] + Cl2
Al + Si4 = Al4Si3 =>
16 Al + 3 Si4 = 4 Al4Si3
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 11/26/23
Equations balanced on 12/26/22
Оставьте нам отзыв о своем опыте работы с химической балансировкой уравнений.