Equations balanced on the previous day | Equations balanced on the next day |
3 FeSO3 + K2Cr2O7 + 4 H2SO4 = 3 FeSO4 + K2SO4 + Cr2(SO4)3 + 4 H2O
KMnO4 + C2H5OH + HCl = CH3COOH + KCl + MnCl2 + H2O =>
4 KMnO4 + 5 C2H5OH + 12 HCl = 5 CH3COOH + 4 KCl + 4 MnCl2 + 11 H2O
CoCl2 + (NH4)2O = Co(NH4)2 + Cl2O =>
CoCl2 + (NH4)2O = Co(NH4)2 + Cl2O
Ae + CuBr2 = AeBr + Cu =>
2 Ae + CuBr2 = 2 AeBr + Cu
NaNO3 + HCOOH = HNO3 + NaCOOH =>
NaNO3 + HCOOH = HNO3 + NaCOOH
Ca + H2 = CaH2 =>
Ca + H2 = CaH2
Ae + CuBr2 = AeBr + Cu =>
2 Ae + CuBr2 = 2 AeBr + Cu
Fe(OH)2 = HOH + FeO =>
Fe(OH)2 = HOH + FeO
H5IO6 + Ba(OH)2 = Ba5(IO6)2 + H2O =>
2 H5IO6 + 5 Ba(OH)2 = Ba5(IO6)2 + 10 H2O
CH4 + F2 = CF4 + HF =>
CH4 + 4 F2 = CF4 + 4 HF
Ae + CuBr2 = AeBr + Cu =>
2 Ae + CuBr2 = 2 AeBr + Cu
H5IO6 + Ba(OH)2 = Ba5(IO6)2 + H2O =>
2 H5IO6 + 5 Ba(OH)2 = Ba5(IO6)2 + 10 H2O
Mn(OH)4 = MnO2 + H2O =>
Mn(OH)4 = MnO2 + 2 H2O
H5IO6 + Ba(OH)2 = Ba5(IO6)2 + H2O =>
2 H5IO6 + 5 Ba(OH)2 = Ba5(IO6)2 + 10 H2O
C4H8 + KMnO4 + H2SO4 = C3H6O + K2SO4 + MnSO4 + H2O =>
15 C4H8 + 8 KMnO4 + 12 H2SO4 = 20 C3H6O + 4 K2SO4 + 8 MnSO4 + 12 H2O
Si4O4C8H24 + O2 = SiCO2 + H2O + CO2 =>
Si4O4C8H24 + 12 O2 = 4 SiCO2 + 12 H2O + 4 CO2
FeSO3 + K2Cr2O7 + H2SO4 = Fe2(SO4)3 + K2SO4 + Cr2(SO4)3 + H2O =>
2 FeSO3 + K2Cr2O7 + 5 H2SO4 = Fe2(SO4)3 + K2SO4 + Cr2(SO4)3 + 5 H2O
C14H30 + O21 = CO2 + H2O =>
21 C14H30 + 43 O21 = 294 CO2 + 315 H2O
BrF = Br2 + F2 =>
2 BrF = Br2 + F2
Fe + S = Fe2S2 =>
2 Fe + 2 S = Fe2S2
K2Cr2O7 + H2SO4 + FeSO3 = Cr2(SO4)3 + Fe2SO4 + H2O + K2SO4 =>
K2Cr2O7 + H2SO4 + 6 FeSO3 = Cr2(SO4)3 + 3 Fe2SO4 + H2O + K2SO4
H5IO6 + Ba(OH)2 = Ba5(IO6)2 + H2O =>
2 H5IO6 + 5 Ba(OH)2 = Ba5(IO6)2 + 10 H2O
Ae + CuBr2 = AeBr + Cu =>
2 Ae + CuBr2 = 2 AeBr + Cu
K2Cr2O7 + H2SO4 + FeSO3 = Cr2(SO4)3 + Fe2SO4 + H2O + K2SO4 =>
K2Cr2O7 + H2SO4 + 6 FeSO3 = Cr2(SO4)3 + 3 Fe2SO4 + H2O + K2SO4
C3H6OC3H6 + O2 = CO2 + H2O =>
2 C3H6OC3H6 + 17 O2 = 12 CO2 + 12 H2O
CH3CH2CH2CH2CH2CH2CH2CH2CH2CH3 + O2 = CO2 + H2O =>
2 CH3CH2CH2CH2CH2CH2CH2CH2CH2CH3 + 31 O2 = 20 CO2 + 22 H2O
H5IO6 + Ba(OH)2 = Ba5(IO6)2 + H2O =>
2 H5IO6 + 5 Ba(OH)2 = Ba5(IO6)2 + 10 H2O
Ge + S = GeS3 =>
Ge + 3 S = GeS3
H{+} + Cr2O7{2-} + S{2-} = S + Cr{3-} + H2O =>
14 H{+} + Cr2O7{2-} + 9 S{2-} = 9 S + 2 Cr{3-} + 7 H2O
Zn(OH)2 + NH4(NO3) = Zn(NO3)2 + NH4OH =>
Zn(OH)2 + 2 NH4(NO3) = Zn(NO3)2 + 2 NH4OH
H{+} + Cr2O7{2-} + S{2-} = S + Cr{3-} + H2O =>
14 H{+} + Cr2O7{2-} + 9 S{2-} = 9 S + 2 Cr{3-} + 7 H2O
Tl2O3 + H2O = HTlO2 =>
Tl2O3 + H2O = 2 HTlO2
AlBr3 + K2S = KBr + Al2S3 =>
2 AlBr3 + 3 K2S = 6 KBr + Al2S3
C12H22O11(s) + O2 = CO2(g) + H2O(aq) =>
C12H22O11(s) + 12 O2 = 12 CO2(g) + 11 H2O(aq)
H{+} + Cr2O7{2-} + S{2-} = S + Cr{3-} + H2O =>
14 H{+} + Cr2O7{2-} + 9 S{2-} = 9 S + 2 Cr{3-} + 7 H2O
(NH4)2SO4 + Ca(OH)2 = (NH4)(OH) + Ca2(SO4)2 =>
2(NH4)2SO4 + 2 Ca(OH)2 = 4(NH4)(OH) + Ca2(SO4)2
K2Cr2O7 + H2SO4 + FeSO3 = Cr2(SO4)3 + Fe2SO4 + H2O + K2SO4 =>
K2Cr2O7 + H2SO4 + 6 FeSO3 = Cr2(SO4)3 + 3 Fe2SO4 + H2O + K2SO4
Ae + CuBr2 = AeBr + Cu =>
2 Ae + CuBr2 = 2 AeBr + Cu
H{+} + Cr2O7{2-} + S{2-} = S + Cr{3-} + H2O =>
14 H{+} + Cr2O7{2-} + 9 S{2-} = 9 S + 2 Cr{3-} + 7 H2O
Ga(BrO)3 + Rb = Rb3(BrO)3 + Ga =>
Ga(BrO)3 + 3 Rb = Rb3(BrO)3 + Ga
CaOCO2 = CaO + CO2 =>
CaOCO2 = CaO + CO2
(HClO4) + (Ba(OH)2) = Ba(ClO4)2 + H2O =>
2(HClO4) + (Ba(OH)2) = Ba(ClO4)2 + 2 H2O
K2C2O4 + AgNO3 = C2Ag2O4 + KNO3 =>
K2C2O4 + 2 AgNO3 = C2Ag2O4 + 2 KNO3
Ba2 + N = Ba2N =>
Ba2 + N = Ba2N
H{+} + Cr2O7{2-} + S{2-} = S + Cr{3-} + H2O =>
14 H{+} + Cr2O7{2-} + 9 S{2-} = 9 S + 2 Cr{3-} + 7 H2O
Ae + CuBr2 = AeBr + Cu =>
2 Ae + CuBr2 = 2 AeBr + Cu
H{+} + Cr2O7{2-} + S{2-} = S + Cr{3-} + H2O =>
14 H{+} + Cr2O7{2-} + 9 S{2-} = 9 S + 2 Cr{3-} + 7 H2O
H5IO6 + Ba(OH)2 = Ba5(IO6)2 + H2O =>
2 H5IO6 + 5 Ba(OH)2 = Ba5(IO6)2 + 10 H2O
(NH4)2SO4 + BaF2 = NH4F + BaSO4 =>
(NH4)2SO4 + BaF2 = 2 NH4F + BaSO4
C2H6O2 + O2 = CO2 + H2O =>
2 C2H6O2 + 5 O2 = 4 CO2 + 6 H2O
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 11/26/23
Equations balanced on 12/26/22
Оставьте нам отзыв о своем опыте работы с химической балансировкой уравнений.